Author Topic: Qs (pls help) (Read 1600 times) Tweet Share

monokekie · « **on:** July 09, 2009, 01:54:55 pm »

[IMG]http://img268.imageshack.us/img268/9792/ch11exq9.png[/img]
(source:cambridge essential)
tkx!

Damo17 · « **Reply #1 on:** July 09, 2009, 02:51:12 pm »

Quote from: monokekie on July 09, 2009, 01:54:55 pm

[IMG]http://img268.imageshack.us/img268/9792/ch11exq9.png[/img]
(source:cambridge essential)
tkx!

part d)
from part c: $p= \frac{1}{9(\frac{2}{3})^t+1}$

for $p>\frac{1}{2}$

$\frac{1}{2}< \frac{1}{9(\frac{2}{3})^t+1}$

$\frac{1}{2} (9(\frac{2}{3})^t+1) <1$

$9(\frac{2}{3})^t+1<2$

$(\frac{2}{3})^t < \frac{1}{9}$

$t > \frac{log_e (\frac{1}{9})}{log_e(\frac{2}{3})}$

$t> 5.42$

EDIT: changed the inequality signs for all except last two lines. Got a bit mixed up, sorry.

monokekie · « **Reply #2 on:** July 09, 2009, 02:55:10 pm »

^^^

thanks Damo17! Your solution 's better than the cambridge solution(which i couldn't understand)

d0minicz · « **Reply #3 on:** July 09, 2009, 03:09:00 pm »

lol are those the exercise solutions in pdf form?

monokekie · « **Reply #4 on:** July 09, 2009, 03:10:48 pm »

um, nope. They are in hard copy, for chapter reviews

Quote from: d0minicz on July 09, 2009, 03:09:00 pm

lol are those the exercise solutions in pdf form?

Damo17 · « **Reply #5 on:** July 09, 2009, 03:13:52 pm »

I made a mistake with the inequality signs, post edited.

monokekie · « **Reply #6 on:** July 09, 2009, 03:14:34 pm »

Quote from: Damo17 on July 09, 2009, 03:13:52 pm

I made a mistake with the inequality signs, post edited.

yeah i understood that lol, tkx

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