Login

Welcome, Guest. Please login or register.

July 23, 2025, 04:25:21 pm

Author Topic: VCE Chemistry Question Thread  (Read 2841285 times)  Share 

0 Members and 13 Guests are viewing this topic.

jyce

  • Victorian
  • Forum Obsessive
  • ***
  • Posts: 290
  • Respect: +17
Re: VCE Chemistry Question Thread
« Reply #5355 on: July 12, 2016, 04:23:57 pm »
+1
I have a question.
Why is that acids with different Ka values need the same amount of let's say 0.1 M of NaOH to neutralize it?

Weak acids may only partially ionise in water and to different extents, but they will still completely react with a strong base, such as NaOH. So, for example, although equal moles of ethanoic acid and ammonium ions will ionise to different extents in water, they will be forced to completely ionise in the presence of a strong base. As you have the same amount of ethanoic acid and ammonium ions, and as both are monoprotic, they will both react in the same mole ratio with 0.1 M of NaOH and the same amount of NaOH will be required in each case.
« Last Edit: July 12, 2016, 04:27:27 pm by jyce »

Apink!

  • Victorian
  • Forum Obsessive
  • ***
  • Posts: 396
  • ~just keep swimming
  • Respect: +9
Re: VCE Chemistry Question Thread
« Reply #5356 on: July 12, 2016, 04:28:37 pm »
+1
Thanks jyce! :)

EDIT: I have another question. From NEAP
« Last Edit: July 12, 2016, 05:00:49 pm by Apink! »
2015: Mathematical Methods CAS [42]

2016: English [46], Chemistry [42], Biology [37], Psychology [48], Specialist Mathematics [32]
ATAR: 99.20

jyce

  • Victorian
  • Forum Obsessive
  • ***
  • Posts: 290
  • Respect: +17
Re: VCE Chemistry Question Thread
« Reply #5357 on: July 12, 2016, 05:47:48 pm »
0
Thanks jyce! :)

EDIT: I have another question. From NEAP

The reaction would be slower with the hydrochloric acid. Hydrochloric acid is a (much) stronger acid than hypobromous acid. Therefore, a lower concentration of hydrochloric acid would be needed to create a solution of the same pH. A lower concentration of a reactant = a slower rate of reaction.

I *THINK* that's the answer. You wouldn't happen to have the solutions to confirm, would you?


Actually, I changed my mind. The rates would be the same! If each reaction has the same pH, then they have the same concentration of protons, and it's the protons that react with the base. Same concentration of protons (and same concentration of base, which the question states) = same rate of reaction!
« Last Edit: July 12, 2016, 05:54:49 pm by jyce »

Syndicate

  • Forum Leader
  • ****
  • Posts: 797
  • Hard work beats Talent
  • Respect: +139
Re: VCE Chemistry Question Thread
« Reply #5358 on: July 12, 2016, 06:10:40 pm »
0
Hey guys,

How can one distinguish that a molecular compound ionises in water, and others don't?
2017: Chemistry | Physics | English | Specialist Mathematics | Mathematics Methods
2018-2020 : Bachelor of Biomedicine at University of Melbourne

Physics Guide 2017

lzxnl

  • Victorian
  • ATAR Notes Legend
  • *******
  • Posts: 3432
  • Respect: +215
Re: VCE Chemistry Question Thread
« Reply #5359 on: July 12, 2016, 07:03:35 pm »
+2
The reaction would be slower with the hydrochloric acid. Hydrochloric acid is a (much) stronger acid than hypobromous acid. Therefore, a lower concentration of hydrochloric acid would be needed to create a solution of the same pH. A lower concentration of a reactant = a slower rate of reaction.

I *THINK* that's the answer. You wouldn't happen to have the solutions to confirm, would you?


Actually, I changed my mind. The rates would be the same! If each reaction has the same pH, then they have the same concentration of protons, and it's the protons that react with the base. Same concentration of protons (and same concentration of base, which the question states) = same rate of reaction!

Your first point is halfway there. Initially, your second statement is correct. Same pH, same rate of reaction. But over time, as there's evidently a higher concentration of HOBr, the proton concentration decreases slower than that for HCl (can also think of this in terms of Le Chatelier's principle). So the rate of reaction involving HOBr would be higher during the reaction.

Hey guys,

How can one distinguish that a molecular compound ionises in water, and others don't?

Molecular compounds that ionise in water tend to be acids or bases. Think about it.
2012
Mathematical Methods (50) Chinese SL (45~52)

2013
English Language (50) Chemistry (50) Specialist Mathematics (49~54.9) Physics (49) UMEP Physics (96%) ATAR 99.95

2014-2016: University of Melbourne, Bachelor of Science, Diploma in Mathematical Sciences (Applied Maths)

2017-2018: Master of Science (Applied Mathematics)

2019-2024: PhD, MIT (Applied Mathematics)

Accepting students for VCE tutoring in Maths Methods, Specialist Maths and Physics! (and university maths/physics too) PM for more details

student1122

  • Victorian
  • Adventurer
  • *
  • Posts: 16
  • Respect: 0
Re: VCE Chemistry Question Thread
« Reply #5360 on: July 12, 2016, 07:16:47 pm »
+1
Hey guys,

How can one distinguish that a molecular compound ionises in water, and others don't?

Hey,
If it is an ionic compound it will ionise in water (if you remember from unit 1/2)
Chemstriy (45) Methosd (46) Specialist (50) Further (44) Accounting (43) English Language (38)

HopefulLawStudent

  • Victorian
  • Forum Leader
  • ****
  • Posts: 822
  • Respect: +168
Re: VCE Chemistry Question Thread
« Reply #5361 on: July 13, 2016, 11:15:12 pm »
0
Quote
For methyl orange:

HMe(aq) + H20(l) <--> H3O+(aq) + Me-(aq)
         Red                    Yellow

In acid solutions, the equilibrium shifts left, therefore the solution becomes red.

Could someone please explain how we know that the equilibrium shifts left in acid solutions?

HighTide

  • Victorian
  • Forum Obsessive
  • ***
  • Posts: 208
  • Sink or swim
  • Respect: +48
Re: VCE Chemistry Question Thread
« Reply #5362 on: July 14, 2016, 09:00:04 am »
+4
Could someone please explain how we know that the equilibrium shifts left in acid solutions?
Never actually seen this, but I assume you're referring to when an acid is added.
If an acid is added, you increase the overall hydronium ion concentration, and by Le Chaterlier's principle, the equilibrium has to shift to the left as it favours the backward reaction (since more H3O+).

After googling, the acidic properties of metal hydrides: https://en.wikipedia.org/wiki/Transition_metal_hydride
It says they may be weak acids. Weak acid means they don't fully ionise in water. I.e. they're equilibrium constant is low, and the backward reaction is preferred, hence equilibrium shifts to the left.

Again, this was just a guess from what I saw on the wikipedia page. Jyce or |zxn| may know the acidic properties of HMe's and be able to explain it better.
2014-2015: VCE
2016-2018: Bachelor of Biomedical Science

jyce

  • Victorian
  • Forum Obsessive
  • ***
  • Posts: 290
  • Respect: +17
Re: VCE Chemistry Question Thread
« Reply #5363 on: July 14, 2016, 03:57:17 pm »
+1
Never actually seen this, but I assume you're referring to when an acid is added.
If an acid is added, you increase the overall hydronium ion concentration, and by Le Chaterlier's principle, the equilibrium has to shift to the left as it favours the backward reaction (since more H3O+).

Sounds good to me  :)
« Last Edit: July 14, 2016, 03:58:49 pm by jyce »

jazzaa36

  • Forum Regular
  • **
  • Posts: 55
  • Respect: 0
Re: VCE Chemistry Question Thread
« Reply #5364 on: July 14, 2016, 07:37:21 pm »
+1
Hello :) I got a few questions i need help with...

1. heparin is an organic compound produced by the body to stop blood clotting. Structural analysis shows heparin to be a repeating disaccharide with numerous sulfonic acid groups and carboxyl groups bonded to the structure.

a) the sulfonic acid groups and carboxyl groups on the heparin molecules are completely ionised when they are in the blood. What conclusion can be made about the pH of blood?

Would it be 7? not 100% sure

2. The process of preventing blood clotting by the drug involves two steps.
Step 1: The drug bonds strongly to an enzyme inhibitor molecule, which then changes shape
Step 2: This new shape of the inhibitor can now attach to the active site of the enzyme, which normally catalyses the blood clotting reaction.

a) Based on the structure of the drug molecule (similar structure of heparin but contains an extra OH on the 5'), suggest which type of bonding is most likely to occur between the drug and enzyme inhibitor molecule.

hydrogen bonding?

b) Outline why the attachment of the inhibitor molecule to the active site of the enzyme prevents blooding clotting.
???


THANKS IN ADVANCE  ;D

keltingmeith

  • Honorary Moderator
  • Great Wonder of ATAR Notes
  • *******
  • Posts: 5493
  • he/him - they is also fine
  • Respect: +1292
Re: VCE Chemistry Question Thread
« Reply #5365 on: July 14, 2016, 07:59:48 pm »
+1
Hello :) I got a few questions i need help with...

1. heparin is an organic compound produced by the body to stop blood clotting. Structural analysis shows heparin to be a repeating disaccharide with numerous sulfonic acid groups and carboxyl groups bonded to the structure.

a) the sulfonic acid groups and carboxyl groups on the heparin molecules are completely ionised when they are in the blood. What conclusion can be made about the pH of blood?

Would it be 7? not 100% sure

Bahahah, loving the draw on knowledge here. ;) You're right in that blood's pH is about 7, but it's actually slightly basic. Take note of the question - it's not asking you to give a numerical value, it's asking you to make a conclusion about the pH. This means you can simply make a statement - is it acidic, basic, or neutral?

This is slightly trickier in that it's kind of like an amino acid question - what does an amino acid look like when it's in acidic, basic, and neutral pHs? At neutral, it's zwitterionic (acid protonated, base deprotonated), at acidic, both are protonated, at basic, both are deprotonated. You can use this guide to decide if regular acids or bases will be protonated or deprotonated at particular pHs.

Using this information, if your acids are completely ionised, this means that they've all donated their protons, so we have a deprotonated acid (or a conjugate base). This means that the sugar is likely in a basic environment - and so, blood must be basic. (a quick google search tells me the pH of blood is ~7.4, so we're good!)

2. The process of preventing blood clotting by the drug involves two steps.
Step 1: The drug bonds strongly to an enzyme inhibitor molecule, which then changes shape
Step 2: This new shape of the inhibitor can now attach to the active site of the enzyme, which normally catalyses the blood clotting reaction.

a) Based on the structure of the drug molecule (similar structure of heparin but contains an extra OH on the 5'), suggest which type of bonding is most likely to occur between the drug and enzyme inhibitor molecule.

hydrogen bonding?

You certainly could form hydrogen bonds - there's also the potential for ionic bonds to form, as well, since the carboxylic groups are there.

b) Outline why the attachment of the inhibitor molecule to the active site of the enzyme prevents blooding clotting.
???

So for blood to clot, it needs to get into the enzyme. If it can't, because there's an inhibitor in the way, it can't get into the enzyme! Remember the lock and key model - only one substrate can get in at a time. So if something blocks up the active site, no other molecules can get in, preventing blood clotting.

mary1911997

  • Adventurer
  • *
  • Posts: 16
  • Respect: 0
  • School: Penola Catholic college
  • School Grad Year: 2016
Re: VCE Chemistry Question Thread
« Reply #5366 on: July 14, 2016, 10:59:57 pm »
0
hi guys
i have a question in my prac report which i am stuck with and i have no clue of how to do it and any help is appreciated
so i have attached the prac link and my results are
http://amrita.olabs.edu.in/?sub=73&brch=8&sim=142&cnt=2
we used 2M HCl instead of 1M and 0.25M of sodium thiosulfate instead of 0.1M

volume of HCl                   V(Na2S2O3)                   V(H2O)       
5 ml                                     10 ml                                35 ml     
5 ml                                      25 ml                               20ml
5 ml                                     40 ml                                5 ml
5 ml                                     45 ml                                0 ml

and i am not being able to figure out question 3 which is : calculate the concentration on sodium thiosulfate in each reaction


kind regards

Jakeybaby

  • Trendsetter
  • **
  • Posts: 191
  • Grad Year: 2016
  • Respect: +23
Re: VCE Chemistry Question Thread
« Reply #5367 on: July 14, 2016, 11:04:56 pm »
0
hi guys
i have a question in my prac report which i am stuck with and i have no clue of how to do it and any help is appreciated
so i have attached the prac link and my results are
http://amrita.olabs.edu.in/?sub=73&brch=8&sim=142&cnt=2
we used 2M HCl instead of 1M and 0.25M of sodium thiosulfate instead of 0.1M

volume of HCl                   V(Na2S2O3)                   V(H2O)       
5 ml                                     10 ml                                35 ml     
5 ml                                      25 ml                               20ml
5 ml                                     40 ml                                5 ml
5 ml                                     45 ml                                0 ml

and i am not being able to figure out question 3 which is : calculate the concentration on sodium thiosulfate in each reaction


kind regards
Were you not using a concentration of 0.25M for the Sodium Thiosulfate as you stated in your question?

- Jake
2016 ATAR: 98.60

2020: Bachelor of Finance @ University of Adelaide

Recipient of the 2017 University of Adelaide Principals' Scholarship

mary1911997

  • Adventurer
  • *
  • Posts: 16
  • Respect: 0
  • School: Penola Catholic college
  • School Grad Year: 2016
Re: VCE Chemistry Question Thread
« Reply #5368 on: July 14, 2016, 11:32:24 pm »
0
Were you not using a concentration of 0.25M for the Sodium Thiosulfate as you stated in your question?

- Jake


we used 0.25M of sodium thiosulfate

Sine

  • Werewolf
  • National Moderator
  • Great Wonder of ATAR Notes
  • *****
  • Posts: 5132
  • Respect: +2103
Re: VCE Chemistry Question Thread
« Reply #5369 on: July 14, 2016, 11:33:49 pm »
0
use the dilution formula.
C1V1 = C2V2

For the first reaction
C1 = 0.25M
V1 = 10mL
C2 = ?
V2 = 50mL

Sub these values into the equation to solve for the "new" concentration.

You don't need to use units in litres as the mL units will cancel out.