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November 08, 2025, 08:17:29 am

Author Topic: methods3/4 q's  (Read 1069 times)  Share 

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Nato

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methods3/4 q's
« on: January 11, 2014, 05:12:49 pm »
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does the remainder theorem work when diving some polynomial by a quadratic?

such as trying to find the remainder when (from essentials textbook) is divided by . Can this be done without having to do the whole long division?

cheers.
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Orb

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Re: methods3/4 q's
« Reply #1 on: January 11, 2014, 05:30:34 pm »
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does the remainder theorem work when diving some polynomial by a quadratic?

such as trying to find the remainder when (from essentials textbook) is divided by . Can this be done without having to do the whole long division?

cheers.

There's a thread for 3/4 MM questions btw.

But anyway, I don't believe that the remainder theorem can be used to apply in this circumstance. You can't simply sub in x=1 to find the solution because x^2 is made out of (x+1)(x-1).

So yeah, you should just divide the polynomial through the long division method.
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psyxwar

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Re: methods3/4 q's
« Reply #2 on: January 11, 2014, 07:07:48 pm »
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After looking through my essentials, I found the question:

Given that P(x) can be written in the form , where Q(x) is a polynomial and a and b are constants, hence or otherwise, find the remainder when P(x) is divided by





Adding the two equations we get: , from which we get and

Therefore, the remainder, which is ax+b, is 6x-4.
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Nato

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Re: methods3/4 q's
« Reply #3 on: January 12, 2014, 02:32:00 pm »
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this is from essentials.

Well, the graph of is shown. Then we are told to graph (question a) ->  by 'applying suitable transformations'. I don't think we're supposed to expand it or anything.

I am finding it hard to see the transformations that have taken place. Can anyone provide any hints? Like, could the equation be arranged a certain way?

thanks
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Phy124

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Re: methods3/4 q's
« Reply #4 on: January 12, 2014, 03:23:36 pm »
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If and then they are related by i.e. the graph of is obtained by translating one unit to the right.
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