Info: The experiment is testing amylase efficiency at varying temperatures. The concentration of starch left in the test tubes 1-5 after they've been heated is compared to a set of standards-iodine's used. The control in the experiment has no amylase in it and was left at 24 degrees celsius.
Just want some opinions on my answers to these enzyme experiment questions!
Explain why it is important to have a set of standards?Standard solutions are of known starch concentration. They, therefore, provide a colour comparison for starch concentrations in test tubes 1-5. This colour comparison helps in identifying the amount of starch that has been catalysed by amylase into maltose and/or glucose during the experiment, and therefore amylase's overall efficiency at varying temperatures.
Consider what you've put in the control tube. List 2 features of the way this tube was set up that are important for controlling he experiment.There was no enzyme present in the control tube and the test tube was left at room temperature (25 degrees celsius). Therefore, no starch catabolism was shown in the control tube over the duration of 10 minutes. This control serves as a comparison for test-tubes 2-5 as it was not exposed to varying factors, such as temperature.
The control will adopt a black-blue colour under iodine presence where as test tubes 2-4 will change colour. (Test tube 5 was exposed to 80 degrees celsius and thus will become blue black too due to denaturing)This answer is very verbose^ I'm not entirely sure what is necessary and what is not. I think that the last part in italics is unnecessary.
My hypothesis:The enzyme amylase will catalyse most effectively at 37 degrees celsius due to the similarity in temperature to the optimum in humans. As the temperature surpasses the optimum, enzyme efficiency will decrease. No catalysis action will occur at 80 degrees celsius, as the amylase will have denatured and enzyme-substrate complexes will fail to form. Enzymes at temperatures below 37 degrees celsius will lose kinetic energy and thus will catalyse the substrate (starch) at a slower, less effective, rate.
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