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October 22, 2025, 12:23:40 am

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Rishi97

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Rishi's Chemistry Thread
« on: April 07, 2014, 08:46:37 pm »
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Welcome to Rishi's Chemistry Thread :)
Chemistry is a tough subject so I'll need all the help I can get.

Thanks in advance ;)
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Rishi97

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Re: Rishi's Chemistry Thread
« Reply #1 on: April 07, 2014, 08:49:59 pm »
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Why can glucose be oxidised more rapidly to produce energy, than fat?
I don't know if this is a Biology question but it came up while I was doing chem so sorry if I've posted in the wrong section.
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Rishi97

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Re: Rishi's Chemistry Thread
« Reply #2 on: April 07, 2014, 08:58:07 pm »
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On pg 186 of the heinemann textbook, it states that the CH2OH groups on adjacent glucose monomers in starch are on the same side of the polymer chain, while in cellulose, they are on alternating sides. What effect does this have? In regards to the strength of the compound?
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lzxnl

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Re: Rishi's Chemistry Thread
« Reply #3 on: April 07, 2014, 11:01:29 pm »
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Why can glucose be oxidised more rapidly to produce energy, than fat?
I don't know if this is a Biology question but it came up while I was doing chem so sorry if I've posted in the wrong section.

You won't need this for VCE chem, but it probably has something to do with how effective our enzymes are at catalysing each reaction step. Fats and glucose undergo slightly different metabolic processes, but both enter the citric acid cycle at the same place, as acetyl CoA

On pg 186 of the heinemann textbook, it states that the CH2OH groups on adjacent glucose monomers in starch are on the same side of the polymer chain, while in cellulose, they are on alternating sides. What effect does this have? In regards to the strength of the compound?

Enzymes require a very specific substrate for those to fit in the active site. Moving one of the CH2OH groups to the other side changes the shape of the molecule and thus affects the bonding between cellulose and our starch/glycogen hydrolysis enzymes. As it turns out, our enzymes are ineffective here.

As for the strength of the compound, I'm not too sure on this myself; it may well indirectly affect how the glucose monomers bond to form the cellulose polymer. Perhaps with this particular form of glucose, it prefers to form long linear chains, whereas with the form of glucose found in glycogen, the glucose can branch out. I'm not sure if cellulose is any stronger than starch in terms of intermolecular forces, but cellulose is certainly more regular; the uniformity of the hydrogen bonding may allow cellulose to pack together better.
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Rishi97

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Re: Rishi's Chemistry Thread
« Reply #4 on: April 08, 2014, 12:39:09 pm »
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Write an equation to show the formation of a dipeptide from serine and cysteine.
Thanks
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Re: Rishi's Chemistry Thread
« Reply #5 on: April 08, 2014, 05:34:39 pm »
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Molecular equation? Work out the molecular formula of serine and cysteine, add them, and make sure you leave space for a H2O
I'm going to try this from my knowledge of amino acid structures
Cysteine has a CH2-SH side group while serine has a CH2-OH side group. And they're joined to H2N-CH-COOH on carbon 2
OK. So cysteine looks like C3H7O2NS and serine looks like C3H7O3N
Add them together to get C3H7O2NS + C3H7O3N => C6H12O4N2S + H2O
as it's a condensation reaction
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Rishi97

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Re: Rishi's Chemistry Thread
« Reply #6 on: April 09, 2014, 10:25:36 am »
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When a trigylceride is formed, does it undergo an esterification reaction?
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Rishi97

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Re: Rishi's Chemistry Thread
« Reply #7 on: April 09, 2014, 04:13:51 pm »
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Explain why ethanol produced by fermentation is referred to as a ‘biochemical fuel'
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lzxnl

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Re: Rishi's Chemistry Thread
« Reply #8 on: April 09, 2014, 09:22:06 pm »
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When a trigylceride is formed, does it undergo an esterification reaction?

Yes. A triglyceride is a triester of glycerol and three fatty acids.

Explain why ethanol produced by fermentation is referred to as a ‘biochemical fuel'
Thanks

It's produced by biological organisms and it's renewable.
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Rishi97

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Re: Rishi's Chemistry Thread
« Reply #9 on: April 11, 2014, 12:56:49 pm »
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A compound has the molecular formula C3H9X. The atom X is most likely to be:
a) Chlorine
b) Hydrogen
c) Nitrogen
d) Oxygen
I'm confused cause there can't be more than 8 hydrogens so how is there 9?
Thanks
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lzxnl

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Re: Rishi's Chemistry Thread
« Reply #10 on: April 11, 2014, 05:49:07 pm »
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A compound has the molecular formula C3H9X. The atom X is most likely to be:
a) Chlorine
b) Hydrogen
c) Nitrogen
d) Oxygen
I'm confused cause there can't be more than 8 hydrogens so how is there 9?
Thanks
Nitrogen. Look at C3H8 and replace a hydrogen with an amine NH2 group. Look, extra hydrogen
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Rishi97

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Re: Rishi's Chemistry Thread
« Reply #11 on: April 11, 2014, 07:31:27 pm »
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Nitrogen. Look at C3H8 and replace a hydrogen with an amine NH2 group. Look, extra hydrogen

oh wow, that was easy. I went completely blank but now I get it.
Thanks lzxnl
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Rishi97

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Re: Rishi's Chemistry Thread
« Reply #12 on: April 14, 2014, 03:06:34 pm »
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Why is the functioning of the enzyme closely related to its tertiary structure?
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Re: Rishi's Chemistry Thread
« Reply #13 on: April 14, 2014, 03:38:34 pm »
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In order for an enzyme to facilitate reactions, the enzyme's active site must have a complementary shape to the substrates in order to form an enzyme-substrate complex. The tertiary structure determines the shape of the enzyme's active site so it is important for its function because enzymes are specific to their substrates.

Rishi97

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Re: Rishi's Chemistry Thread
« Reply #14 on: April 16, 2014, 12:29:56 pm »
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A student performs two tests on an organic compound. In the first test, 3 mol of the compound was completely reacted with oxygen and 6 mol of carbon dioxide were produced. In the second test a few drops of bromine were added to the compound. The compound did not react rapidly with bromine. The formula of this compound is likely to be:
a) C2H4
b) C2H6
c) C3H8
d) C6H14
Pls show working out. Thanks
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