Sketching f'(x) given f(x) and vise versa

[TheJosh]

Could someone please explain how to draw f(x) graphs from f'(x) graphs would be much appreciated

i'm so confused!!!

[Flaming_Arrow]

please elaborate. is the fuction given? or is it just a graph

[TonyHem]

Hmm nvm not that great at it myself.

[Edmund]

I think he means how to draw the derivative graph for a function, and the opposite.

For a f'(x) graph, whatever below the x axis corresponds to a negative gradient on the original f(x) graph.

And anything above the x axis of a f'(x) graph corresponds to a positive gradient on the f(x) graph.

Any point on the x axis corresponds to a zero gradient.

[TrueTears]

You can remember some general rules

When you differentiate a quartic you get a cubic graph.

A cubic - > parabola

and so on.

[/0]

Just going through the motions:
Where f'(x) = 0 , f(x) has a stationary point.
Where f'(x) < 0 , f(x) has a negative gradient.
Where f'(x) > 0, f(x) has a positive gradient.
Where f'(x) has a local min/max, f(x) will have a point of inflexion.

[TheJosh]

 ohhhh ok i think i see it now

thanks guys appreciate the help