Further Math Exam 1: Answers + Discussion!

[Dan1995]

Networks questions 9? is it really C?

My solutions say D?

[Monodon monoceros]

I could't redraw the 2nd graph or the first graph

[IntelxD]

q3 is the 38th point, which was 50. So when you do the calculation for the upper fence (max value before it becomes an outlier) you do 50+1.5x(50-30)=80, therefore anything above 80 is an outlier, which was only two values.

Yeah, there was no need to use the CAS. The key to answering the question was to determine the number of outliers.

[Dan1995]

I thought networks question 7 was D. I can't seem to redraw the first graph as planar. Can someone post a picture of how they did the first graph as planar?

Take the bottom vertice to the very top, and then redraw the edge from the top right vertice to the bottom left so that it goes around the bottom right?

[phlman]

My solutions say D?

OH , sorry my bad i read it wrong, can you please show me how you got D?

[Dan1995]

I could't redraw the 2nd graph or the first graph

1st one. Take the very bottom  vertice up to the top so its above the top two, then if you redraw the edge from the top right to the bottom left it becomes planar.
2nd one. Swap the bottom left vertice with the place of the bottom right, and redraw the edge between them so it goes around the other vertices, and it becomes planar.

[Lucho23]

Hey guys,

Sorry to ask again and bust everyones balls but for question 6 in core, how did everyone know Q3? I still believe it was E... Lmao unless I'm completely retarded 

Cheers

With Box Plots remember, 25% is below the Q1, 25% between Q1 and Median, 25% between Median and Q3 and 25% above Q3.
With this in mind, you can use the Q3+IQRx01.5 rule to find the upper fence, at which point, any data point greater than or equal to this is an outlier.
This requires a little bit off rough estimating, so Q1 is 25% of 50; Q1 = 12.5. Q3 is 75% of 50; Q3 = 37.5.
Count through and find the 12.5th point and the 37.5th point. They seem to be approximately 29 and 49, respectively.
This means the IQR = 20. Use the rule: Q3+IQRx01.5 so now 49+20x1.5 = 79.
Only two data points lie above 79, therefore, A is the correct option.

[Dan1995]

OH , sorry my bad i read it wrong, can you please show me how you got D?

A and B are not cuts as they do not completely separate the source from the sink.
C has a capacity of 20.
D has a capacity of 18 (as the 4 is not counted).
E has a capacity of 22.

[jaketsorlinis1]

Anybody able to explain why Q9 from number patterns is D when C clearly works. after about 20 days 500 grams are in her body and 200 which is 40 percent is being removed each day. C said less than 200 is the max from each 24 hour peroid therefore it is not true and is what they were asking for

[nugz]

Take the bottom vertice to the very top, and then redraw the edge from the top right vertice to the bottom left so that it goes around the bottom right?

I see it now, thanks.
I'm quite disappointed with 37/40, especially when I got full marks when I did the 2013 one
Do I still have a chance of like mid-40s if I get an A+ for Exam 2?

[Dan1995]

I see it now, thanks.
I'm quite disappointed with 37/40, especially when I got full marks when I did the 2013 one
Do I still have a chance of like mid-40s if I get an A+ for Exam 2?

Yes, it is possible to get 45+ still, depending on your ranking in the cohort and the strength of the cohort, and what range A+ you get (whether you just scrape in with an A+ or a clear of the cutoff by a few marks).

[Addzkebabs]

With Box Plots remember, 25% is below the Q1, 25% between Q1 and Median, 25% between Median and Q3 and 25% above Q3.
With this in mind, you can use the Q3+IQRx01.5 rule to find the upper fence, at which point, any data point greater than or equal to this is an outlier.
This requires a little bit off rough estimating, so Q1 is 25% of 50; Q1 = 12.5. Q3 is 75% of 50; Q3 = 37.5.
Count through and find the 12.5th point and the 37.5th point. They seem to be approximately 29 and 49, respectively.
This means the IQR = 20. Use the rule: Q3+IQRx01.5 so now 49+20x1.5 = 79.
Only two data points lie above 79, therefore, A is the correct option.

Thanks Dan1995 and Lucho23 for the clarification, turns out I just am retarded  Thanks again guys, sorry to be a pain

[Lucho23]

Anybody able to explain why Q9 from number patterns is D when C clearly works. after about 20 days 500 grams are in her body and 200 which is 40 percent is being removed each day. C said less than 200 is the max from each 24 hour peroid therefore it is not true and is what they were asking for

Option C is true, actually.
Try this: Chuck the sequence in a column on a spreadsheets page. In the column next to the sequence, multiple each Dn value by 0.4 (=a1*0.4 and drag this for all cells).
This never reaches 200, therefore showing that the amount leaving her body is always below 200.

[Dan1995]

Thanks Dan1995 and Lucho23 for the clarification, turns out I just am retarded  Thanks again guys, sorry to be a pain

Don't stress, still plenty of marks to make up on exam 2.

[phlman]

A and B are not cuts as they do not completely separate the source from the sink.
C has a capacity of 20.
D has a capacity of 18 (as the 4 is not counted).
E has a capacity of 22.

darn! i forgot that maximum flow = minimum cut , sigh lost two marks. Thanks anyway!