Naming compounds

[uni_student]

Can anyone please tell me the name of these compounds? Very much appreciated!

[Reus]

I need help with this too haha

[kawfee]

You don't have the answers, yeah?

I'm going to give a crack at these

1. ? lol dunno
2. 4,4 dichloro propanoic acid pentanoic
3. ethyl propanoate
4. 3 Bromo 3,5 dimethyl octane

im am not 100 % sure.... someone else should answer this, ahah sorry!

but i know when naming compounds with constituents such as bromo, methyls etc... you should put them in alphabetical order or something

hmm i should look for my rules sheet~ good question!

[Reus]

\
hmm i should look for my rules sheet~ good question!

Could you post it pls?

[Hokiksyo-min]

1. 3-methylhex-5-en-1-ol
2. 4,4-dichloropentanoic acid
3. ethylpropanoate
3-bromo-3,5-dimethyloctane


/\ not 100% sure, but that's my best shot

[uni_student]

Thanks!!! Any idea about this one?

[kawfee]

Sorry could not find it, but will look again!

But for 2... I shall try

C atom in the Carboxy is ALWAYS numbered 1.
And the longest carbon chain has 5 carbons. = pentanoic acid
There are two chloro groups on the same C, ie Carbon numbered 4. = 4,4 dichloro
in 4,4 dichloro < di = because two chloro 4,4 = indicates position for BOTH chloros

therefore 4,4 dichloro pentanoic acid

Ok...that may not have made sense...but I'm assuming you have some knowledge as to naming compounds- so it may make a bit of sense? Ahah sorry!

But for now,

maybe check this http://www.youtube.com/watch?v=yM7A2TL3nd0 <similar problems towards the end
http://www.youtube.com/results?q=nomenclature+vce

and other Nomenclature/Naming videos out?

[kawfee]

uni_student
is the new one you posted up a polymer? as indicated by those squiggly wavy line thing?

if so ... poly-propene ?

[uni_student]

Yep that sounds right, thanks heaps!

I don't suppose anyone knows the answers to these questions as well? Struggling so much with organic them

1. Complete the following equation showing the main organic products. You do not have to balance the equation but all organic compounds should be shown in structural form. If no reaction occurs, write NR.

a. propan-2-ol+KMnO4 →
b. pent-2-ene+HOH and H+ →
c. HO(CH2)3OH+HOOC(CH2)4COOH →

2. Show by means of equations how you could convert propan-1-ol to propanoic acid

3. Show by means of equations how you could convert but-2-yne to 2,2,3-trichlorobutane

4. Arrange the following in order of increasing boiling point and use bonding theory to explain your reasoning:

CH3(CH2)4CH3
C5H11OH
C4H9COOH
CH3C(CH3)2CH2CH3
C4H10

5. 5.00 g of methanol are mixed with 20.0 g of octanoic acid and allowed to react to form an ester. If the reaction has an average yield of 75.0%, what mass of product should be formed?

thanks to anyone who helps!

[Reus]

C atom in the Carboxy is ALWAYS numbered 1.
And the longest carbon chain has 5 carbons. = pentanoic acid
There are two chloro groups on the same C, ie Carbon numbered 4. = 4,4 dichloro
in 4,4 dichloro < di = because two chloro 4,4 = indicates position for BOTH chloros

therefore 4,4 dichloro pentanoic acid

Is it whenever there is a carboxyl group at the end of the longest chain is the suffix always -noic acid?

[Robert123]

Yep that sounds right, thanks heaps!

I don't suppose anyone knows the answers to these questions as well? Struggling so much with organic them

a. propan-2-ol+KMnO4 →
b. pent-2-ene+HOH and H+ →
c. HO(CH2)3OH+HOOC(CH2)4COOH →

2. Show by means of equations how you could convert propan-1-ol to propanoic acid

3. Show by means of equations how you could convert but-2-yne to 2,2,3-trichlorobutane

4. Arrange the following in order of increasing boiling point and use bonding theory to explain your reasoning:

CH3(CH2)4CH3
C5H11OH
C4H9COOH
CH3C(CH3)2CH2CH3
C4H10

5. 5.00 g of methanol are mixed with 20.0 g of octanoic acid and allowed to react to form an ester. If the reaction has an average yield of 75.0%, what mass of product should be formed?

thanks to anyone who helps!

1a is an oxidation reaction. When you oxidase an alkanol, you get a C=O bond. Since this is a secondary alkanol, you will get the ketone CH3COCH3 (I don't know how to name ketones since they aren't in the VCE course, you would need to consult other uni students)
1b  this is an addition reaction with a water (generally known as H2O not HOH ) molecule adding over the double bond. The products would be penta-2-ol and penta-3-ol
1c is an di -alkanol reacting with a di-carboxy which is an esterification reaction resulting in the ester
HOOC(CH2)4COO(CH2)3OH

2. Is an oxidation reaction so you would need to use an oxidant such as Cr2O7 2- in an acidic solution


Most of this stuff is beyond my knowledge level but hopefully that help a bit 

[uni_student]

Thanks that's fantastic!

Got some more questions, from the VCE textbook but no answers:

1. When 0.10 mol of sodium thiosulfate pentahydrate, Na2S2O3•5H2O, is added 500 mL of water, the temperature drops by 2.3°C. What is the ΔH per mole of sodium thiosulfate pentahydrate dissolved? State any two (2) assumptions made in carrying out your calculations.

2. What is the ΔH for the reaction H2(g)+Cl2(g)→2HCl(g) given that:
H2(g)→2H(g)   ΔH=+437kJ
Cl2(g)→2Cl(g)   ΔH=+244kJ
HCl(g)→H(g)+Cl(g)   ΔH=+433kJ

3. Use the ΔH°formation table to determine the enthalpy of combustion of 2-methylpropane at 25°C.

4.The molar enthalpy of combustion of camphor, C10H16O, is -5898 kJ/mol. Use the ΔH°formation table to determine the enthalpy of formation of camphor.

5. The molar enthalpy of combustion of camphor, C10H16O, is -5898 kJ/mol. How much energy is released on combustion of 1 gram of camphor?

6. Use average bond energies given in a table in the appendix to determine the enthalpy of reaction when 1 mole of ethene reacts with oxygen to form carbon dioxide and water.

I'll be incredibly grateful if anyone can give me the answers to these! thank you

[Robert123]

Q1 mass of water is 500g. You should know that to raise 1g of water by 1C requires 4.18kJ (this is known as a calorie, however the calorie you find on nutritiion label on food is actually a kilocalorie and should be spelt with a capital 'C' )
To raise the temperature of all the water by 1C is then equal to 500*4.18= 2090J/C
However, the temperature of the water actually dropped by 2.3C so we multiply it on to get 2090*2.3= ans (I can't be bothered getting a calculator to do this part but you get the drill)
Now that the amount of energy absorbed when 0.1 mol of the stuff was dissolved. To work out how much energy would be absorb by 1 mol, simply divide by 0.1
Ans/0.1=ans2
And that's your delta H value. Since the stuff absorb energy when being dissolved, the delta h value is positive.
Now what assption did we make when doing this. First off, all the energy absorb came from the thermal energy of the water. I'm not entirely sure what the second assumption would be though

[kawfee]

Is it whenever there is a carboxyl group at the end of the longest chain is the suffix always -noic acid?

yes

well i have not come across anything otherwise. but im pretty sure.