Calibration factor equations

[simo101]

While I was writing down the calibration factor equations in my notes and trying to memorise them, I noticed that deltaH=mxcxdeltaT (where c is the specific heat capacity) and Cf=deltaH/deltaT. So therefore does Cf also = mc? As mc = deltaH/deltaT

Sorry if this is a stupid algebraic question but I can't find anything that proves this correct or incorrect

[Yacoubb]

While I was writing down the calibration factor equations in my notes and trying to memorise them, I noticed that deltaH=mxcxdeltaT (where c is the specific heat capacity) and Cf=deltaH/deltaT. So therefore does Cf also = mc? As mc = deltaH/deltaT

Sorry if this is a stupid algebraic question but I can't find anything that proves this correct or incorrect

The change in enthalpy is equal to energy/number of moles. McdeltaT is the energy, so it's in fact mcdeltaT/number of moles. Cf = Energy/T, not deltaT/T.

[simo101]

The change in enthalpy is equal to energy/number of moles. McdeltaT is the energy, so it's in fact mcdeltaT/number of moles. Cf = Energy/T, not deltaT/T.

But if the enthalpy= mass x Cp x deltaT and Cf= energy/deltaT, then shouldn't Cf = mass x Cp because if you move the equation energy = mass x Cp x DeltaT you get mass x Cp = energy/deltaT and energy/deltaT = Cf

[Jason12]

is the energy in these equations always in joules?

[simo101]

is the energy in these equations always in joules?

Yes always in joules, I have found that is a common thing they test in the exams (ie put the calibration factor in kJdegreesC^-1 to try and catch people out)

[speedy]

is the energy in these equations always in joules?

For specific heat capacity, yes. CF can be kJ/mol etc.

[simo101]

The change in enthalpy is equal to energy/number of moles. McdeltaT is the energy, so it's in fact mcdeltaT/number of moles. Cf = Energy/T, not deltaT/T.

Similarly E=VIt and Q=It so therefore Q also equals Q=E/V as E=QV.

I was wondering if I am allowed to alter the E=mass x Cp x deltaT equation like I have above.