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September 10, 2025, 08:03:59 am

Author Topic: Mathematics Question Thread  (Read 1626440 times)  Share 

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RuiAce

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Re: Mathematics Question Thread
« Reply #3465 on: May 23, 2018, 11:04:43 am »
+3
Hello again,

This isn't exactly a maths question, but more a calculator qu :-[ :o
I have a series of questions that include things like "find correct to 2 decimal place cos 0.589", and " find correct to 2 decimal places tan 0.056" etc. They are all along the same lines. Punching that into my calculator is easy enough, but it says it has to be done using the radian mode on my calculator (clearly giving a different answer).....how do I convert my calculator into radian mode?
It is a Casio fx-82AU PLUS.

Sorry I've looked up online manuals but still a bit confused!!  ::) :-[
Thanks!
Code: [Select]
0. Calculator turned on and ready

1. Press "SHIFT", followed by <MODE>.
    - By doing so you go into <SETUP>, instead of <MODE>. That's how the "SHIFT" button works.

2. Choose "Rad"

You can also use this method to go back to degrees.

mxrylyn

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Re: Mathematics Question Thread
« Reply #3466 on: May 28, 2018, 12:37:50 pm »
0
Hello.
I am not quite sure how to differentiate
Ln (2x + 4) (3x - 1)
I have looked at a solution but I dont understand the steps.


RuiAce

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Re: Mathematics Question Thread
« Reply #3467 on: May 28, 2018, 01:32:56 pm »
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Hello.
I am not quite sure how to differentiate
Ln (2x + 4) (3x - 1)
I have looked at a solution but I dont understand the steps.


Did you mean \( [\ln (2x+4) ] \times (3x-1) \) or \( \ln [(2x+4)(3x-1)] \)?

mxrylyn

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Re: Mathematics Question Thread
« Reply #3468 on: May 28, 2018, 01:38:24 pm »
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The questions says in( 2x +4) (3x -1)

But I wasn't sure if the × (3x - 1) was implied

RuiAce

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Re: Mathematics Question Thread
« Reply #3469 on: May 28, 2018, 02:19:03 pm »
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If it was the former then it's just a product rule bash: \( \frac{2}{2x+4}(3x-1) + 3 \ln (2x+4) \)


Therefore \( \frac{d}{dx} \ln [(2x+4)(3x-1)] = \frac{2}{2x+4} + \frac{3}{3x-1} \)

gilliesb18

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Re: Mathematics Question Thread
« Reply #3470 on: May 29, 2018, 05:00:17 pm »
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Hello, just need help on a trig question...
15. A wedge is cut so that its cross-sectional area is a sector of a circle, radius 15cm and subtending an angle pi/6 at the centre. Find
a) the volume of the wedge
b) the surface area of the wedge

Any help is appreciated... I just cant think how to start to work it out..

Thanks heaps:):)

RuiAce

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Re: Mathematics Question Thread
« Reply #3471 on: May 29, 2018, 07:36:37 pm »
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Hello, just need help on a trig question...
15. A wedge is cut so that its cross-sectional area is a sector of a circle, radius 15cm and subtending an angle pi/6 at the centre. Find
a) the volume of the wedge
b) the surface area of the wedge

Any help is appreciated... I just cant think how to start to work it out..

Thanks heaps:):)
The question doesn't provide any assumption on the shape that the wedge originally came from. If it's cylindrical then we're missing its height; if it's spherical or something else then we're lacking in heaps of information.

Mate2425

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Re: Mathematics Question Thread
« Reply #3472 on: May 30, 2018, 01:56:00 pm »
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Hi could i please have help with the working out for this compound interest Question.
Kate has $4,000 in a bank account that pays 5% p.a. with interest paid annually and Rachel has a different account $4,000 paying 4% quarterly. Which person will receive the most interest over 5 yrs and by how much?

ANS: Kate $224.37

Thanks  :)

RuiAce

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Re: Mathematics Question Thread
« Reply #3473 on: May 30, 2018, 02:29:51 pm »
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Hi could i please have help with the working out for this compound interest Question.
Kate has $4,000 in a bank account that pays 5% p.a. with interest paid annually and Rachel has a different account $4,000 paying 4% quarterly. Which person will receive the most interest over 5 yrs and by how much?

ANS: Kate $224.37

Thanks  :)

Note that the rates described are all annual. So 4% p.a. turns into 1% per quarter for Rachel. It also means that Rachel receives interest 4 times a year, not just once at the end.

Note that there is no annuity here. This is just a straightforward application of compound interest by itself.
« Last Edit: May 30, 2018, 02:32:58 pm by RuiAce »

Dragomistress

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Re: Mathematics Question Thread
« Reply #3474 on: May 31, 2018, 08:54:44 pm »
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How am I meant to do this question?

RuiAce

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Re: Mathematics Question Thread
« Reply #3475 on: May 31, 2018, 08:59:50 pm »
+3
How am I meant to do this question?
You know that in degrees, the interior angle sum is \( 180^\circ (n-2) \). So just replace \(180^\circ\) with \( \pi\) to get \(3\pi\).

(Essentially speaking, the smallest angle becomes the first term of your arithmetic progression.)
« Last Edit: May 31, 2018, 09:02:10 pm by RuiAce »

Dragomistress

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Re: Mathematics Question Thread
« Reply #3476 on: June 02, 2018, 11:44:35 am »
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I am wondering how I am meant to do e.

Opengangs

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Re: Mathematics Question Thread
« Reply #3477 on: June 02, 2018, 02:04:00 pm »
+2
I am wondering how I am meant to do e.


So because \( n \) is a solution to the equation, \( 2\cos x = 1 - \frac{1}{2}x \) then any \( x \) that follows must strictly be in between these two bounds. Hence, it follows that the solution \( n \) must also lie in between the two.

kauac

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Re: Mathematics Question Thread
« Reply #3478 on: June 03, 2018, 01:10:11 pm »
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This confuses me every single time:

In Simpson's rule, my teacher has a bit of a mnemonic to remember it, which is:  First + last, 4 x odd and 2 x even.

What would the 'odd' and 'even' be referring to? Like, if you had a table of values, is it whether the x value is an odd/even number? Or is it if you count across from the first and last values, every second one is odd, and the others are even?

Any clarification would be super helpful!  :)
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RuiAce

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Re: Mathematics Question Thread
« Reply #3479 on: June 03, 2018, 01:18:43 pm »
+3
This confuses me every single time:

In Simpson's rule, my teacher has a bit of a mnemonic to remember it, which is:  First + last, 4 x odd and 2 x even.

What would the 'odd' and 'even' be referring to? Like, if you had a table of values, is it whether the x value is an odd/even number? Or is it if you count across from the first and last values, every second one is odd, and the others are even?

Any clarification would be super helpful!  :)

\begin{align*} f(3) &\to \text{first}\\ f(3.2) &\to \text{odd}\\ f(3.4) &\to \text{even}\\ f(3.6)&\to \text{odd}\\ f(3.8 ) &\to \text{even}\\ f(4) &\to \text{odd}\\ f(4.2) &\to \text{even}\\ f(4.4) &\to \text{odd}\\ f(4.6) &\to \text{even}\\ f(4.8 )&\to \text{odd}\\ f(5)&\to \text{last} \end{align*}
That "mnemonic" is a very well known way of memorising the generalised Simpson's rule. Essentially your "first" input value is \(x_0 = 3\). The next input value, \(x_1 = 3.2\), is called "odd" in this context because the index is \(1\). The subsequent input value, \(x_2 = 3.4\), is called "even" in this context because the index is \(2\). And so on.

Essentially, you start counting after the "first". That one, will be the first "odd".

You should always end up with exactly one more "odd" than "even"
« Last Edit: June 03, 2018, 01:20:47 pm by RuiAce »