how do you do b for this question
Plug it in the calculator it is 5/72... I don't really know how to do it the 2U way... You basically chose 2 dice to be the value you want out of the 3.. hence 3 choose 2 (look for nCr button in the calculator, press shift then divide to get the c, 3C2)... you power the number of possibility that is 1/6 by two and the remaining that is NOT 2 by 1 in this case
The 2U way is to just analyse the chances indivdually.
So you have the chance of rolling a 6 as 1 in 6, the chance of not rolling a 6 is 5 in 6. You need two sixes, and one non-six, so you have
^2\times\left(\frac{5}{6}\right))
.
But the dice that isn't a six can be the first, second or third die, so you have 3 different forms of that, so you multiply that by 3 and you get your 5/72.
for this question is the answer for c 3/5
No, the answer is not 3/5 because you have restrictions on the selections you can place.
If you picked one card, yeah the probability would be 3/5 because you can't pick A & D, but when you pick two cards without replacement, restricting two cards the second selection has a probability of 2/4. tbh you could list out all the possibilities, since there are 20 (10, and their reverses, see which don't have A and/or D) and you'd still get the same answer. FYI the answer is for that is 3/10.
How do you do b for this question
If you've drawn your Venn diagram correctly, you'll have 12 doing music only, 7 doing music and sports, 2 doing nothing and 9 doing sports only.
Since you're picking two different people, its without replacement ie your answer will be
\times\left(\frac{8}{29}\right)=\frac{12}{145})
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