Mathematics Question Thread

[Shadowxo]

I was just wondering how to do this log question:

3000 = 100e^n

So 30 = eⁿ
loge(30) = n

[jamonwindeyer]

I was just wondering how to do this log question:

3000 = 100e^n

Welcome to the forums! Shadow's got you covered - But if you've only just started Logs it might not be super clear how it works. Be sure to let us know if you need it clarified, or if you need help finding stuff around the site

[joyg]

Thanks for the help, i'll be sure to ask around if i get lost 

[asd987]

Hi can i get some help with this question. thanks

[jamonwindeyer]

Hi can i get some help with this question. thanks

This is a bit of manipulation of the Log Laws! Namely, \(\log{a}+\log{b}=\log{ab}\):



Note that \(\log_7{7}=1\), by definition! Does this help?

[Shadowxo]

Hi can i get some help with this question. thanks

14 is 7*2
So log₇(14) = log₇(7*2) = log₇7 + log₇2 = 1 + log₇2
Does this help? Second question is done in same way as the first

Edit: someone beat me to it

[joyg]

Another day and another question

Can you please help me with: 0.5M = Me^0.116k

Thanks for your help 

[RuiAce]

Another day and another question

Can you please help me with: 0.5M = Me^0.116k

Thanks for your help 

Note, if M=0 then any value of k would work. Generally not necessary for 2U though.

[joyg]

All good, thanks for the help 

[Hplovers]

How to solve this:

Express y in terms of x if:

dy/dx = 2/x²

I understand i need to find the primitive function but just not sure how to

Answer is y = -2/x + C

Thankyouu!

[kiwiberry]

How to solve this:

Express y in terms of x if:

dy/dx = 2/x²

I understand i need to find the primitive function but just not sure how to

Answer is y = -2/x + C

Thankyouu!

dy/dx = 2/x² = 2x^-2
\(\therefore \,y=2\times \frac{x^{-1}}{-1}+c= \frac{-2}{x}+c\)

[RuiAce]

How to solve this:

Express y in terms of x if:

dy/dx = 2/x²

I understand i need to find the primitive function but just not sure how to

Answer is y = -2/x + C

Thankyouu!

dy/dx = 2/x² = 2x^-2
\(\therefore \,y=2\times \frac{x^{-1}}{-1}+c= \frac{-2}{x}+c\)

Go for the

Code: [Select]

[tex] [/tex]tags rather than the

Code: [Select]

\( \) ones. Those bracket tags are more for when you have an equation in between ordinary text like \(this\)

[kiwiberry]

Go for the

Code: [Select]

[tex] [/tex]tags rather than the

Code: [Select]

\( \) ones. Those bracket tags are more for when you have an equation in between ordinary text like \(this\)

Ah ok, sorry haha will do next time!

[RuiAce]

Ah ok, sorry haha will do next time!

You get used to it. Starting LaTeX in high school ain't the easiest thing to do. Doesn't take too much effort but shouldn't come immediately either.

[levendibigd]

Hi there, can I please have help expressing |a+b| without any absolute values, by using the properties of absolute values