Hello, I am new to this forum and am not sure if this has been posted or not.
This is from one of my schools past HSC trial paper. I need help with the whole question except for c) (I can do it myself after i find all the other answers)
(Image removed from quote.)
Thank you cuties!
Hey! So, the equation we have been given is

and we want to rewrite it in standard form. First, we need to complete the square, as the final answer is in the form (x-h)^2. So,
-7=2((x-2)^2-4)-7=2(x-2)^2-15)
And that's our answer! We got
^2-15)
Great! Now, we want to calculate the roots of the function. The easiest way of doing this is the quadratic equation.
(-7)}}{2(2)}=4\pm\sqrt{30})
Easy as

Now, with all of the above information (and subbing in x=0, y=0 etc.) you can easily sketch the graph!
For the last part, we essentially want to know where f(x) is ABOVE the x-axis. We know the function is a positive parabola, so this will occur to either side of the roots (ie. to the left of the first x intercept, and to the right of the second x intercept). This will become super obvious once you draw the sketch
