Can someone pls solve this question
Kim has three red shirts and two yellow shirts. On each of the three days,
Monday, Tuesday and Wednesday, she selects one shirt at random to wear. Kim
wears each shirt that she selects only once.
(i) What is the probability that Kim wears a red shirt on Monday? 1
(ii) What is the probability that Kim wears a shirt of the same colour on all
three days?
1
(iii) What is the probability that Kim does not wear a shirt of the same colour
on consecutive days?
(i) 3 red shirts, 5 shirts altogether. Thus, probability is 3/5
(ii) If she were to wear a red shirt on Monday, she'd have to wear a red shirt on Tuesday and Wednesday.
(3/5)(2/4)(1/3)
She can't wear a yellow shirt on the three consecutive days.
Thus, the probability is simply (3/5)(2/4)(1/3) = 1/10
(iii) P(not wear a shirt of the same colour) = P(RYR) + P(YRY) = (3/5)(2/4)(2/3) + (2/5)(3/4)(1/3) = 18/60 = 3/10