3U Maths Question Thread

[anotherworld2b]

I was doing this question but i got the wrong answer. I am not sure what i did wrong

[RuiAce]

I was doing this question but i got the wrong answer. I am not sure what i did wrong

Line 3: Error in differentiation

dy/dx = -(...)^-2 . ( 2 + 6x )

[anotherworld2b]

oh I see now Thank you for the help RuiAce

Line 3: Error in differentiation

dy/dx = -(...)^-2 . ( 2 + 6x )

[anotherworld2b]

For this question I'm not sure what I have to do

[jamonwindeyer]

For this question I'm not sure what I have to do

Cool question! Think of this like a production line - The composite function is really just two functions performed one after the other. The question is asking what can come out the end of the conveyor belt, given what we are putting in to the conveyor belt (that is, the domain given the range).

Consider the first as an example. Putting the numbers -2, -1, 0, 1, 2 into the first box, \(f(x)=x^2\), yields the numbers 0, 1 and 4. When you put those numbers in the second box, \(g(x)=2x-3\), you get:



So the range of the composite function in the first case is -3, -1, 5. Note that it might be a little weird writing a discrete range like this, but since we have a finite set of numbers given in the domain, we'll get a finite set of numbers as our range

[bsdfjnlkasn]

Hey, thanks for the detailed response, I haven't been taught this thoroughly yet so your answer really helped.
I was just wondering how these lines of working help me get R = 5? I understand how to get the answer by equating coefficients and using the identity but is the first (quoted) line the beginning a different method for obtaining the same answer? If not, would these lines be helpful in solving other questions based off the same congruency statement?

[RuiAce]

Hey, thanks for the detailed response, I haven't been taught this thoroughly yet so your answer really helped.
I was just wondering how these lines of working help me get R = 5? I understand how to get the answer by equating coefficients and using the identity but is the first (quoted) line the beginning a different method for obtaining the same answer? If not, would these lines be helpful in solving other questions based off the same congruency statement?

Those lines of working seek to prove the formula I quoted at the very start.

In your case, since a = 4 and b = 3, clearly upon substitution we have R = √(4^2+3^2) = 5.

This is not HSC content. This belongs in the preliminary course. If you are not familiar with it then you will need to go back to your notes regarding preliminary trigonometry.

[Rathin]

Hey, thanks for the detailed response, I haven't been taught this thoroughly yet so your answer really helped.
I was just wondering how these lines of working help me get R = 5? I understand how to get the answer by equating coefficients and using the identity but is the first (quoted) line the beginning a different method for obtaining the same answer? If not, would these lines be helpful in solving other questions based off the same congruency statement?

A small rule to remember when converting to the auxiliary form:
acosx+bsinx ≡ Rcos(x-a)
acosx-bsinx ≡ Rcos(x+a)
asinx+bcosx ≡ Rsin(x+a)
asinx+bcosx ≡ Rsin(x-a)

The part of Rui's answer you quoted is just the derivation. R is denoted as the amplitude in the auxiliary form and is given by square rooting the squared the two coefficients. E.g  3cosx+4sinx ≡ Rcos(x-a) is the same as to match the correct auxiliary form 4sinx+3cosx ≡ Rsin(x+a)..where R is given by sqrt(4^2 + 3^2) =5 and the auxiliary angle which is responsible for a lateral shift is given by tan^-1(3/4) and note that the values for the angle are absolute as we are trying to find the smallest angle.

[RuiAce]

So the question you asked 3cosx+4sinx ≡ Rsin(x+a)..the transformation is actually wrong..it should be 3cosx+4sinx ≡ Rcos(x-a)

No, to this bit only. Because you can simply rewrite the LHS as 4sinx+3cosx

[Rathin]

No, to this bit only. Because you can simply rewrite the LHS as 4sinx+3cosx

Oh yes..sorry my bad..

EDIT: Original Post has been modified.

[shreya_ajoshi]

How many numbers greater than 4000 can be formed from the figures 3,5,7,8,9? (repetitions not allowed)

In how many ways can the letters of the word permute be arranged if (i) the first and last places are occupied by consonants, (ii) the vowels and consonants occupy alternate places?

[RuiAce]

How many numbers greater than 4000 can be formed from the figures 3,5,7,8,9? (repetitions not allowed)

In how many ways can the letters of the word permute be arranged if (i) the first and last places are occupied by consonants, (ii) the vowels and consonants occupy alternate places?

Question 1 is too arbitrary. Is there a restriction on how many digits that can be used? (Since you gave 5 digits for a 4-digit number.)
_______________________

[anotherworld2b]

Thank you for your help jamon. Can i please have help with these two questions?

[bsdfjnlkasn]

(I know this is a really simple question but I don't know what the t-formulae is and what it's used for)

Substituting the t-formulae for cos x and sin x into the equation 3sinx+cosx = 4 produces what quadratic equation?

[RuiAce]

(I know this is a really simple question but I don't know what the t-formulae is and what it's used for)

Substituting the t-formulae for cos x and sin x into the equation 3sinx+cosx = 4 produces what quadratic equation?

This method is kinda inferior to the auxiliary angle transformation for trigonometric equations if you ask me. It's used in Extension 2 for some bizarre integrals.