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October 19, 2025, 12:55:27 pm

Author Topic: 3U Maths Question Thread  (Read 1515984 times)  Share 

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anotherworld2b

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Re: 3U Maths Question Thread
« Reply #2430 on: July 16, 2017, 02:02:29 pm »
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Could I leave the last line as the answer? In the book the answer is 3In1.5
You haven't used any log rules in that photo (unless it just got chopped off), but everything I see is most certainly correct.

RuiAce

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Re: 3U Maths Question Thread
« Reply #2431 on: July 16, 2017, 02:10:10 pm »
+1
Yeah it's fine. Their answer is just nicer.

anotherworld2b

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Re: 3U Maths Question Thread
« Reply #2432 on: July 16, 2017, 02:19:05 pm »
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I was wondering how did they get their answer?
Yeah it's fine. Their answer is just nicer.

RuiAce

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Re: 3U Maths Question Thread
« Reply #2433 on: July 16, 2017, 02:21:19 pm »
+1
I was wondering how did they get their answer?


RuiAce

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anotherworld2b

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Re: 3U Maths Question Thread
« Reply #2436 on: July 16, 2017, 04:49:11 pm »
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I tried to do this question but I am not sure what I did wrong

caitlinlddouglas

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Re: 3U Maths Question Thread
« Reply #2437 on: July 16, 2017, 08:52:13 pm »
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hi i was wondering how to do ii) and iii) on this question. I'm stuck on ii) and am confused about the terms add to be the coefficient of x^(k+1) in (1=x)^n.
Thanks heaps!
This is the question
http://i.imgur.com/vOXsF0c.png

Shadowxo

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Re: 3U Maths Question Thread
« Reply #2438 on: July 16, 2017, 09:05:27 pm »
+1
I tried to do this question but I am not sure what I did wrong
I can't see any error in your working (except omitting the modulus sign for ln|x+2|, but that wouldn't make any difference) and your answer seems right, what did the answers say?
Also I'm not sure what you did in lines 3-7? I believe for this question you just needed to say dx/dt = 1/(t+2) then x= integral of 1/(t+2)dt and go from there.
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RuiAce

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Re: 3U Maths Question Thread
« Reply #2439 on: July 16, 2017, 09:12:45 pm »
+2
hi i was wondering how to do ii) and iii) on this question. I'm stuck on ii) and am confused about the terms add to be the coefficient of x^(k+1) in (1=x)^n.
Thanks heaps!
This is the question
http://i.imgur.com/vOXsF0c.png
tagged: 2004






Also, part iii should not be done by the binomial theorem, but just by brute force algebra.
« Last Edit: October 10, 2017, 09:18:00 pm by RuiAce »

anotherworld2b

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Re: 3U Maths Question Thread
« Reply #2440 on: July 16, 2017, 09:34:41 pm »
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the answer is x = In (t +2) /2 apparently?
I'm not quite sure how they got that answer

I can't see any error in your working (except omitting the modulus sign for ln|x+2|, but that wouldn't make any difference) and your answer seems right, what did the answers say?
Also I'm not sure what you did in lines 3-7? I believe for this question you just needed to say dx/dt = 1/(t+2) then x= integral of 1/(t+2)dt and go from there.

kiwiberry

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Re: 3U Maths Question Thread
« Reply #2441 on: July 16, 2017, 09:43:21 pm »
+1
the answer is x = In (t +2) /2 apparently?
I'm not quite sure how they got that answer
They've used this log law again, your answer is the same as theirs :)
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anotherworld2b

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Re: 3U Maths Question Thread
« Reply #2442 on: July 16, 2017, 09:54:05 pm »
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Ah I see :)
Would it be incorrect to the leave the answer as it is? Or is a fraction form simply preferred?

They've used this log law again, your answer is the same as theirs :)


kiwiberry

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Re: 3U Maths Question Thread
« Reply #2443 on: July 16, 2017, 10:29:33 pm »
+1
Ah I see :)
Would it be incorrect to the leave the answer as it is? Or is a fraction form simply preferred?

You may be marked correct if you left it as is, but to be safe you should always simplify your answer as far as possible :)
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winstondarmawan

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Re: 3U Maths Question Thread
« Reply #2444 on: July 16, 2017, 11:09:46 pm »
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