So sorry to be here again! its just that I don't have access to teachers and I don't even go to school anymore, if someone can explain this to me it'll be real good!
I worked out Q1 (hope its right)
1) 20.0 g of N2 and 20.0 g of O2 are placed in a metal container with a volume of 12.0 L at a temperature of 200°C. What is the pressure in the container?
Pressure of N2:
n: 20g/ 28.0= 0.71
V: 12L
T: 200 degrees or 473K
P= 0.71x8.31x473/12
P= 232.6kPa
Pressure of O2:
n= 20g/32.0= 0.625
P= 0.63x8.31x473/12
P= 206.4kPa
Total Pressure: 206.4+ 232.6= 439kPa
2)
A spark causes the gases in question 14 to react to form NO2. Assuming the reaction goes to completion and that there is no charge in temperature or volume, what is the pressure in the container after reaction?
Hey! This out
pretty far outside the HSC curriculum, but I've done PV=nRT in uni and it looks like the first question was done correctly! For the second one, we start by writing out a chemical equation.
}+2O_{2(g)} \rightarrow 2NO_{2(g)})
Clearly, the molar ratio is 1:2. Now, let's work out the moles of each of the substance. Actually, you've already done that!


For everyone one mole of Nitrogen, two moles of Oxygen is required. So, Oxygen will be the limiting reagent (ie. it will be completely reacted before the Nitrogen is completely reacted). So, if 0.625 moles of Oxygen is reacted, nitrogen will react in HALF of the molar quantity (0.3125 moles).
So, we know that there are 0 moles of Oxygen, 0.71-0.3125=0.3975 moles of Nitrogen, and 0.625 moles of NO2 in the final system. Use the partial pressure technique above to find the total pressure!