why did you change 15 a to 56pi/3? shouldn't it be 40pi/3? the y is already squared you dont have to sqaure the 9 again! it's 1/9 not 1/81. but please correct me if im wrong.
Hey! Woops, sorry about that, must have had a version cross when editing the formatting this morning; managed to upload one of my first versions of the solutions from prior to upload; just changed it back! Sorry for confusion

Question 15a is incorrect, for whatever reason you decided to square root the curves, and in doing so took out 1/9 but you didnt square root this. If you are going to do this method it should be 1/3 outside the sqrt(36-4x^2). Although I dont know why you have done this in the first place, we are asked for volume which requires y^2 anyway.
Technically, to perform a volume of revolution you should consider a function; which these aren't. To be most correct I first considered only the top half of \(C_1\) and \(C_2\), and then squared these in the formula. You are right, it gives the same result though! They wouldn't have enforced this in the HSC marking mind you, just going straight to \(y^2\) and \(x^2\) is definitely okay too

Good catch on the intermediate error though; I'll tidy that up for sure! But the answer is correct (as of the edit I've just made, again, sorry for the confusing version cross)
