Okay peeps I got a few questions about some of my answers:
Q3a- how good did our graph have to be in order to get the full 2 marks? I got all the points and the asymptotes but i fear my graph drawing skills aren't exactly perefct (i.e the graph above y=2 wasn't a very good reflection of the graph below it)
Q4c- could we have left it as (16/81)^6 and gotten the mark, or did we have to simplify?
Q5a. iv- I used the second derivative test to determine the nature of the stationary point- d'you reckon they'd count that as valid?
Q5b. i- I stated that because the range of the inverse function was equal to the original's domain, you take the negative- would this be fine?
Q6a- did we have to include the unit per unit?
Q6b- I added 'units' to the end of my answer, because it asked for average value- that's not a problem, right?
Q8a- I antidifferentiated the x^(k-1) equation to get an expression, but then I left it there- could I still get 1 mark?
Q8b. ii-I stated that the median value was found from the integral from 0 to m, where m is the median value, which would equal 0.5. I then got the answer from part b (i) and approximated that using e=2.5, giving me an approximation of 13/25. I then stated that the median value would have to be greater the 1/e due to the area from 1/e to 1 being greater than 0.5. Would this allow me to get the full 2 marks?
Thanks heaps!! 
3a) - VCAA provided you with a grid, so I think they're assuming you're calculating each point to get a close to perfect graph, so that it's to scale. However if you've labelled all the points, and the graph's only worth 2 marks, you might be able to get away with it. Don't quote me on that though.
4c) - In the Study Design, it's been pointed out that VCAA expects all answers to be in the simplest form. Many people put down (16/81)^6, though, since it's a follow-on from part a). Can't confirm you'll get the marks, but likely you will!
5a) - 2nd derivative is not on the Methods Study Design, so it's not accepted as valid working. People in Spesh tend to fall into the trap of taking the easy way out and double diffing.
5b) - That sounds reasonable, but depending on how you word it, it may or may not explain why you actually choose the negative solution. As long as you infer that you're choosing the -ve solution so it fits within the domain of the original (or range of inverse), you should be fine.
6a) - Back in my day I was always told to put units in when they ask for area, rate of change and other things. Not really sure if it matters, but it's a safeguard in case they are harsh and look for units! Highly unlikely to get penalised though.
6b) - No, that's not a problem.
8a) - What do you mean by "you left it there"? The question asked to show using differentiation, not anti-diff though. I'm not sure if that'll pass as valid.
8bii) - That's exactly what I've written in my suggested solutions, except in Maths form! So yes, that's perfect.
Good luck for Exam 2!