Hello
I am currently stuck on this quesiton
y= 2cos2(x) + 3sin(2x) where the domain is between negative pie and positive pie and it needs me to sketch the graph
I have tried but I am still stuck on this question, any help would be appreciated
Thank you
Hey !
This question is definitely inside the scope of the methods course however only extremely rarely crops up (last time it came up was like 1997

)
Addition of ordinates is so annoying an tedious but these tips should hopefully help
Graph both graphs on the one set of axis i.e. 2os(2x) and 3sin(2x).
Since the graph we want to graph is the sum of these two "all" we need to do is take each x-value - find both y-values and add them together. Simple? not really gets pretty messy.
To make it easier for you find the x-intercepts of each graph and the y-value of our required graph will be at the EXACT same y-value as the other graph (the one which doesn't have the x-intercept at that point).
Also when each graph has the negative value of the other graph i.e. y=2.524 and y=-2.524 we can conclude that the graph we required will have a x-intercept at that point. (y=0).
Other points can be found by adding the y-value of both graphs i.e. y=2 and y=3 , then we can say that the y-value we require for our graph is y=5.