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November 04, 2025, 05:16:20 pm

Author Topic: Discussion and Suggested Solutions - Mathematics 2017  (Read 87904 times)

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Anything

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Re: Discussion and Suggested Solutions - Mathematics 2017
« Reply #15 on: October 23, 2017, 05:48:00 pm »
Wait there was a fucked up series this year??

Perhaps referring to the question that asked for values of a to make a limiting sum = 2 where a is the first term

Opengangs

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Re: Discussion and Suggested Solutions - Mathematics 2017
« Reply #16 on: October 23, 2017, 05:48:19 pm »
welp, there goes my 100/100 dream after that atrocious silly mistake of M_16 = 0 fml
everything else felt pretty easy, I bs'ed the iso proof tho.

Dylpickle01

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Re: Discussion and Suggested Solutions - Mathematics 2017
« Reply #17 on: October 23, 2017, 05:50:33 pm »
I bs'ed the iso proof tho.

Same
Did anyone manage to get the x value for the bicycles?
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RuiAce

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Re: Discussion and Suggested Solutions - Mathematics 2017
« Reply #18 on: October 23, 2017, 05:51:18 pm »
Perhaps referring to the question that asked for values of a to make a limiting sum = 2 where a is the first term
Lol that's new.

Anything

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Re: Discussion and Suggested Solutions - Mathematics 2017
« Reply #19 on: October 23, 2017, 05:51:52 pm »
Lol that's new.


They didn't give any values, aside from the limiting sum having to equal 2

Dylpickle01

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Re: Discussion and Suggested Solutions - Mathematics 2017
« Reply #20 on: October 23, 2017, 05:52:04 pm »
Lol that's new.

Weren't given r either
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itsAnuu

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Re: Discussion and Suggested Solutions - Mathematics 2017
« Reply #21 on: October 23, 2017, 05:52:21 pm »
0 < a < 4 was the answer
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RuiAce

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Re: Discussion and Suggested Solutions - Mathematics 2017
« Reply #22 on: October 23, 2017, 05:52:49 pm »
Ok that's very new. I'll have to wait for Jamon to show me the question itself then...

Opengangs

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Re: Discussion and Suggested Solutions - Mathematics 2017
« Reply #23 on: October 23, 2017, 05:54:26 pm »
They didn't give any values, aside from the limiting sum having to equal 2
Use the fact that |r| < 1 for a limiting sum to exist

a/(1 - r) = 2
a = 2(1 - r)
Now, -1 < r < 1
1 > -r > -1
2 > 1 - r > 0
4 > a > 0

itsAnuu

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Re: Discussion and Suggested Solutions - Mathematics 2017
« Reply #24 on: October 23, 2017, 05:55:07 pm »
Use the fact that |r| < 1 for a limiting sum to exist

yeh easy q
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1MARIE1

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Re: Discussion and Suggested Solutions - Mathematics 2017
« Reply #25 on: October 23, 2017, 05:56:10 pm »
yeh easy q
Wasn't it worth like 3 marks? or was it 2?
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RuiAce

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Re: Discussion and Suggested Solutions - Mathematics 2017
« Reply #26 on: October 23, 2017, 05:57:58 pm »
Use the fact that |r| < 1 for a limiting sum to exist

a/(1 - r) = 2
a = 2(1 - r)
Now, -1 < r < 1
1 > -r > -1
2 > 1 - r > 0
4 > a > 0
Ahh right. After I saw what was above I instantly questioned if it had to do with the |r|<1 scenario.

Still though, I want to see the exact wording of this Q...

RuiAce

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Re: Discussion and Suggested Solutions - Mathematics 2017
« Reply #27 on: October 23, 2017, 05:58:55 pm »
yeh easy q
It's honestly so hard to call a question easy these days. Especially for some people in the middle of the actual exam.

Because whereas the computations can be fairly simple, trying to get that moment of inspiration to getting started isn't so simple for some.

ellybubble

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Re: Discussion and Suggested Solutions - Mathematics 2017
« Reply #28 on: October 23, 2017, 05:59:43 pm »
Wasn't it worth like 3 marks? or was it 2?
i think it was worth 3 marks, so quite alot
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Re: Discussion and Suggested Solutions - Mathematics 2017
« Reply #29 on: October 23, 2017, 05:59:56 pm »
that paper was harder than expected tbh, I didn't have enough time to go over and check my answers
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