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July 16, 2026, 06:53:18 pm

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kdgamz

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exam questions..
« on: October 02, 2009, 01:41:12 pm »
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Im a bit confused with VCAA exam 1..clarification would be appreciated...

question 1. a)
the answer is but i wrote

am i allowed to do this?

if so then part b) becomes -1/9, whereas the answer says 1/9 because it used

are both acceptable??


thanks

TonyHem

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Re: exam questions..
« Reply #1 on: October 02, 2009, 01:45:28 pm »
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2xy-9y^2 + 9 = 0.
and when y = 1,
2x(1)-9(1)+9 = 0
x = 0
So -1/(0-9(1)) = 1/9

kamil9876

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Re: exam questions..
« Reply #2 on: October 02, 2009, 01:59:00 pm »
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if so then part b) becomes -1/9, whereas the answer says 1/9 because it used

I don't even know the question but I can tell from here that what you are saying is not true. Notice that:



Since you can get one from the other by multiplying by . What this means is that for any and . The two expressions must be the same, hence if some x and y give 1/9 for one expression, they must give 1/9 for the other.
Voltaire: "There is an astonishing imagination even in the science of mathematics ... We repeat, there is far more imagination in the head of Archimedes than in that of Homer."

kdgamz

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Re: exam questions..
« Reply #3 on: October 02, 2009, 02:01:21 pm »
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if so then part b) becomes -1/9, whereas the answer says 1/9 because it used

I don't even know the question but I can tell from here that what you are saying is not true. Notice that:



Since you can get one from the other by multiplying by . What this means is that for any and . The two expressions must be the same, hence if some x and y give 1/9 for one expression, they must give 1/9 for the other.

thats the thing it becomes -1/9  for the expression i used, and 1/9 for the expression in the answer..

this is 2006 VCAA exam 1

EDIT: sorry i just realised :laugh:
« Last Edit: October 02, 2009, 02:04:56 pm by kdgamz »