same here just wanted to check if i would get marks for attempting though
9c,
I worked out M=-1 but was not able to work out C. Is this one mark?
9d,
If i simply wrote let Tangent of AC = Tangent of CB (without working out the tangents) do you guys think thats worth any marks. I also was able to conclude that the tangent of AC occurred at 1/9 and the gradient of the tangent was 1. But did not go further due to the confusion with the graph and domain of the gradient (0,1).
Also thank you so much for your help guys.
m=-1 should get you a mark imo
hmm depends how they mark for your 2nd question if heaps don't do well you could get a mark but I wouldn't count on it
Do any of yous reckon it is possible to get over a 40 is methods with a combined score across both exams of 100/120? Or even with low 30's exam 1 and high 60s-low 70s exam 2?
yeah it's possible but you'd want exam 2 to be hard
For question 7B i), wouldn't the answer be -1 as it's asking for the "largest possible value", and -1>-3?
it is true that -1 is a larger number than -3 but the domain given was from - infinity to c.
and we can't go below 0 to a negative number since the range of g must be in the domain of f (which is all positive numbers including 0)
Range is [0, infinity) not [1,infinity)
which question
for the first [1,inifnity) the domain is restricted of f (good trick by vcaa imo)
for the 2nd the min output of g(x) is 0 so the min of f(g(x) = sqrt(0+1) = 1