Author Topic: Help Please! Methods unit 2 Circular Functions (Read 1053 times) Tweet Share

cheunga · « **on:** November 12, 2017, 03:49:02 pm »

I would really appreciate if someone can please help me with questions c, d & e (attached) - without using calculator. Many thanks!!

VanillaRice · « **Reply #1 on:** November 12, 2017, 04:31:15 pm »

Question 6c)
$ \sin{(\theta-\frac{\pi}{3})}=\frac{-1}{2}\\ \text{We need to establish our basic angle, which is } -\frac{\pi}{6}\\ \theta-\frac{\pi}{3}=-\frac{\pi}{6} + 2\pi n \text{ or } -\frac{5\pi}{6} + 2\pi n \text{ where n is an integer}\\ \theta=\frac{\pi}{6} + 2\pi n \text{ or } -\frac{\pi}{2} + 2\pi n \\ \text{Recall our domain } 0 \leqslant \theta \leqslant 2\pi \\ \text{Substitute in values of n to get solutions within the domain} \\ \theta = \frac{\pi}{6}\, ,\frac{3\pi}{2} $

Hope that helps

I'll let you attempt parts d and e by yourself - post if you're still stuck.

cheunga · « **Reply #2 on:** November 12, 2017, 05:38:42 pm »

Hi, thanks very much for replying. Unfortunately, I don't understand what to do after you find the base angle. If you could dumb it down for me by showing me the working out, that might help. THanks again.

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Author Topic: Help Please! Methods unit 2 Circular Functions (Read 1053 times) Tweet Share

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Help Please! Methods unit 2 Circular Functions

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