Logarithms/Exponentials 2u question (answered)

[88siege]

Im not sure if i'm overthinking for this question but i've been trying to solve simultaneously and idk where to go from there, do we just have to sub in x=-1 into both equations and prove they both give the same answer hence they intersect at x=-1??

Show that the curves y=x^2 and y=e^(x+1) intersect at x=-1

Help is appreciated!!

[RuiAce]

Yeah, at a time like that all you can do is sub in \(x=-1\) and verify you get the same \(y\) value both ways.

There is no way to solve \(x^2 = e^{x+1} \) using elementary methods

[88siege]

Oh okay Thanks!!!