Maths Methods (Exam 2): Discussion, Questions & Potential Solutions

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Has everyone sat the exam? Or are there still people doing it at a later date?

That wasn’t easy but I feel like it was so much better than last years!

Did anyone else get 41 for the number of trials and what did people get for the very last question?

I got 39

[vox nihili]

Just going to remind everyone that a lot of hardwork goes into making the exam and therefore VCAA have copyrighted their exams. As a responsible organisation that wants to see this forum exist for a long time in the future, we cannot release a copy of the exam nor can we allow you to exchange one here either.
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Congratulations to you all for finishing up Methods. It's a bloody hard subject that will pay dividends as you progress onto further study next year and beyond.

[DinWell]

I got 39

Same. I think you had to make Pr(X>1) > .99 so 1-Pr(X=0)-Pr(X=1)>.99. Then solve for n

[Dais_Deorum]

Thoughts on A+ cutoff?

[Lear]

Thoughts on A+ cutoff?

Between 66-69/80

[Freddie Hg]

Same. I think you had to make Pr(X>1) > .99 so 1-Pr(X=0)-Pr(X=1)>.99. Then solve for n

i did exactly this? but didnt get 39?i got somewhere near high 20s i cant remember exactly what

[DinWell]

i did exactly this? but didnt get 39?i got somewhere near high 20s i cant remember exactly what

Hmm. Did you end up solving Don't remember what p was.

[DoingExamsATM]

damn then  i didnt get that? are you talking about the smallest number of n, for p hat to be greater than 0.99

Just gonna drop in, for that question I got n = 39 or something. I'm confident with the answer but I'm not sure if I used a valid method, I created function(n)=binomialcdf(defined with n parameter as max and amount), then subbed in random values of n until it's just above 0.99. This is basically the equivalent of putting it onto a spreadsheet and observing for the value of n.

[Lear]

i did exactly this? but didnt get 39?i got somewhere near high 20s i cant remember exactly what

You got 27 because you did x>=1 instead of x>1.

[integrationbyrecognition]

 lol why am I the only one who found today's exam harder than last years

[Freddie Hg]

You got 27 because you did x>=1 instead of x>1.

but i did pr(x=0) plus pr(x=1)? thats odd  you guys are right probably a calculating error on my behalf

[DinWell]

Just gonna drop in, for that question I got n = 39 or something. I'm confident with the answer but I'm not sure if I used a valid method, I created function(n)=binomialcdf(defined with n parameter as max and amount), then subbed in random values of n until it's just above 0.99. This is basically the equivalent of putting it onto a spreadsheet and observing for the value of n.

How did you write it out on the exam? Did you use calculator notation?

[Dais_Deorum]

Between 66-69/80

Tbh think thats an overestimation. The highest cutoff in the last 7 years was 67-68, and tbh our's wasn't the easiest in that time frame. I'm calling 66, but will have to wait and see!

[ThomasBur]

Does anyone recall what the probability was for the 'find value of n' question?

[crawlingvines]

lol why am I the only one who found today's exam harder than last years

I'm in the same boat as you D: