Maths Methods (Exam 2): Discussion, Questions & Potential Solutions

[Freddie Hg]

Does anyone recall what the probability was for the 'find value of n' question?

its 39. just checked my calculator, its definitely 39

[userrrname]

How are people saying yesterdays was harder??????? Did we get different exams???? With the exception of the last question yesterday, today’s one was ten times harder.

[DoingExamsATM]

How did you write it out on the exam? Did you use calculator notation?

I written something like "this is equal to binomial cdf with lower = 1, upper = n, number trials = n, probability = [whatever it was]". Not quite calculator notation, but in a way that's like "it's pretty obvious this is just using some kind of calculator function with these values". As far as I know, that's allowed, since it's not like I written "binomcdf(n,thing,thing)".

The issue is that I also written "trial and error: insert n = [value], then pr = 0.6 which is <0.99", then a couple more lines to show I got to n = 39 being just above 0.99

[Edged]

What did people get for the distance PQ?

[DinWell]

What did people get for the distance PQ?

I got around 1.910. Was it 3 d.p.?

[undefined]

What did people get for the distance PQ?

1.91m but other people got 1.90 so I'm not sure

Edit: 1.90835472m

[Dais_Deorum]

What about the values of a for which f(x) had no solutions? (Last part of question 1)

[integrationbyrecognition]

for the distance question (3 marks) would i get 1/3 for finding the gradient of the line segment PQ?

[DinWell]

What about the values of a for which f(x) had no solutions? (Last part of question 1)

I got a>root(14)+3

[Dais_Deorum]

I got a>root(14)+3

Yep same

[Nason]

I also got 1 square unit lol fairly certain it's wrong though

I'm seeing a lot of people get 1 squared unit for that one, including myself. for the area between g(x) and its inverse I got 1/4 however.

[Freddie Hg]

1.91m but other people got 1.90 so I'm not sure

Edit: 1.90835472m

yeah i got 1.91

[Freddie Hg]

I got a>root(14)+3

i got this with another answer,

[Nason]

i got this with another answer,

Pretty sure the other answer was a<3-sqrt(14) or something.

I did the same but I just realized it's wrong as a>0

[DinWell]

i got this with another answer,

Did you also say a<3-root(14)? I think you had to exclude that because p(x) has more than 1 turning point with those values.