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April 13, 2026, 07:06:31 pm

Author Topic: turning pt?  (Read 1069 times)  Share 

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lacoste

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turning pt?
« on: November 01, 2009, 02:40:06 pm »
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For the function f : (–∞, a)→ R, f(x)= x2 + 2x
a. find the maximum value of a such that the inverse function f –1 exists.


how do you find the turning pt from that graph, ive forgotten?

d0minicz

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Re: turning pt?
« Reply #1 on: November 01, 2009, 02:43:48 pm »
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derive it
let it equal 0 and sub that x value into original
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lacoste

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Re: turning pt?
« Reply #2 on: November 01, 2009, 02:48:48 pm »
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thanks

ed_saifa

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Re: turning pt?
« Reply #3 on: November 01, 2009, 02:53:59 pm »
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Complete the square
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lacoste

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Re: turning pt?
« Reply #4 on: November 01, 2009, 02:57:57 pm »
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thanks ed saifa and dominicz

QuantumJG

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Re: turning pt?
« Reply #5 on: November 01, 2009, 03:49:28 pm »
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For the function f : (–∞, a)→ R, f(x)= x2 + 2x
a. find the maximum value of a such that the inverse function f –1 exists.


how do you find the turning pt from that graph, ive forgotten?

simple differentiate the function, set f'(x)=0 and solve!

f'(x) = 2x + 2

let f'(x) = 0 => x + 1 = 0 => x =-1 = amax

i.e. f –1 exists iff a -1
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lacoste

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Re: turning pt?
« Reply #6 on: November 01, 2009, 04:00:42 pm »
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cheers