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October 19, 2025, 08:26:13 pm

Author Topic: Solutions for Modules 1 and 2 please??  (Read 5426 times)  Share 

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sathanas

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Re: Solutions for Modules 1 and 2 please??
« Reply #15 on: November 02, 2009, 06:15:49 pm »
I believe module two is wrong.

Question 6 you guys have A as the answer, which corresponds to 21.5 degrees.

It asks, the angle of depression of D FROM A. So, you calculate the angle of A. Also, the hint is in "depression". Many of you seem to have found angle D, which is elevation.

Either way, just my opinion and nothing official..

Answer should be 68.5 I think.



then aren't you meant to take 68.5 from 90 which gives 21.5? or you can find angle D which is 21.5 and then the angle of depression from A is that too because theyre alternate angles.

lankygator

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Re: Solutions for Modules 1 and 2 please??
« Reply #16 on: November 02, 2009, 06:58:11 pm »
question 9 anyone??? workings??

chanel

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Re: Solutions for Modules 1 and 2 please??
« Reply #17 on: November 02, 2009, 07:21:52 pm »
has anyone yet got module 1?

lankygator

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Re: Solutions for Modules 1 and 2 please??
« Reply #18 on: November 02, 2009, 08:49:25 pm »
please this is annoying the shit outta me does any one have the answer to geometry question 9

rustic_metal

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Re: Solutions for Modules 1 and 2 please??
« Reply #19 on: November 02, 2009, 08:52:15 pm »
please this is annoying the shit outta me does any one have the answer to geometry question 9


well thats just S***,  does anyone have the workings to question 9 geometry???

To find the distance from the pole to the wall (y), I equated herron's formula with 1/2bh:

s = (6+4+5)/2 = 7.5

A= root(s(s-6)(s-4)(s-5)) = 1/2 x 6 x y

y = root(s(s-6)(s-4)(s-5))/3 = 3.307m

Then we want the height up the wall when the pole is leaning on it:

x^2 + y^2 = 4^2
.: x = root(4^2 - y^2) = 2.25m ~ 2.3m

.: C