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October 19, 2025, 01:05:12 pm
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Author Topic: Solutions for Modules 1 and 2 please??  (Read 5425 times)  Share 

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Gun

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Solutions for Modules 1 and 2 please??
« on: November 02, 2009, 02:20:01 pm »
?
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griga

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Re: Solutions for Modules 1 and 2 please??
« Reply #1 on: November 02, 2009, 02:24:56 pm »
DDBBCAABD

really not sure though
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sir0004

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Re: Solutions for Modules 1 and 2 please??
« Reply #2 on: November 02, 2009, 02:27:15 pm »
for module 2, i got
DDEBCAABC
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OG-KonG

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Re: Solutions for Modules 1 and 2 please??
« Reply #3 on: November 02, 2009, 02:31:52 pm »
Question 8 is wrong you didnt convert to Metres, rather you left it in MM(milimetres)
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Gun

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Re: Solutions for Modules 1 and 2 please??
« Reply #4 on: November 02, 2009, 02:32:42 pm »
8 was B i converted from M to mm and got 42
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phanphy

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Re: Solutions for Modules 1 and 2 please??
« Reply #5 on: November 02, 2009, 02:33:45 pm »
Quote from: sir0004 on November 02, 2009, 02:27:15 pm
for module 2, i got
DDEBCAABC

I got the same for geom & trig
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Fireworks

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Re: Solutions for Modules 1 and 2 please??
« Reply #6 on: November 02, 2009, 02:35:13 pm »
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billz1508

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Re: Solutions for Modules 1 and 2 please??
« Reply #7 on: November 02, 2009, 02:38:38 pm »
module 1 anyone?
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Craxe

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Re: Solutions for Modules 1 and 2 please??
« Reply #8 on: November 02, 2009, 03:05:17 pm »
For uestion 8 of geometry i got 4 (i.e. A)... that wrong?

Did you guys convert the mm^3 to cm^3, and then divide by 1000?
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hbailey2

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Re: Solutions for Modules 1 and 2 please??
« Reply #9 on: November 02, 2009, 03:09:23 pm »
Quote from: Craxe on November 02, 2009, 03:05:17 pm
For uestion 8 of geometry i got 4 (i.e. A)... that wrong?

Did you guys convert the mm^3 to cm^3, and then divide by 1000?


u find area of the hose face --> Pi*12.5^2
then *length of the hose
=41724.3cm^3
1000cm^c=1L
thus answer is (B) 42*
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Craxe

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Re: Solutions for Modules 1 and 2 please??
« Reply #10 on: November 02, 2009, 03:12:04 pm »
You have a mistake there

The area of your hose face: Pi*12.5^2

12.5 is mm
in cm - its 1.25

so its 1.25^2 * Pi * length of house
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hayley-ho.xx

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Re: Solutions for Modules 1 and 2 please??
« Reply #11 on: November 02, 2009, 05:16:37 pm »
Module 2, I got:
DDEBCAABC

Same as you Fireworks and Phanphy :)
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krzysiek

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Re: Solutions for Modules 1 and 2 please??
« Reply #12 on: November 02, 2009, 06:06:41 pm »
I believe module two is wrong.

Question 6 you guys have A as the answer, which corresponds to 21.5 degrees.

It asks, the angle of depression of D FROM A. So, you calculate the angle of A. Also, the hint is in "depression". Many of you seem to have found angle D, which is elevation.

Either way, just my opinion and nothing official..

Answer should be 68.5 I think.

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rustic_metal

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Re: Solutions for Modules 1 and 2 please??
« Reply #13 on: November 02, 2009, 06:09:47 pm »
Quote from: krzysiek on November 02, 2009, 06:06:41 pm
I believe module two is wrong.

Question 6 you guys have A as the answer, which corresponds to 21.5 degrees.

It asks, the angle of depression of D FROM A. So, you calculate the angle of A. Also, the hint is in "depression". Many of you seem to have found angle D, which is elevation.

Either way, just my opinion and nothing official..

Answer should be 68.5 I think.




The angle of Depression from D from A is equivalent to the angle of Elevation from D to A: The angle RDA
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magnum

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Re: Solutions for Modules 1 and 2 please??
« Reply #14 on: November 02, 2009, 06:15:08 pm »


Another way you could do it is:

1. Angle of depression is always from the horizontal

2. Therefore, find angle RAD (which as you said is 68.5) and then subtract this from 90: (90 - 68.5 = 21.5)

Hope that clears everything up  :)
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