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October 31, 2025, 03:20:41 am

Author Topic: SUGGESTED SOLUTION....  (Read 2749 times)  Share 

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chelo

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SUGGESTED SOLUTION....
« on: November 06, 2009, 11:20:54 am »
Part 1
« Last Edit: November 06, 2009, 11:24:10 am by chelo »

THem

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Re: SUGGESTED SOLUTION....
« Reply #1 on: November 06, 2009, 11:28:06 am »
you can't spell quotient
lol

chelo

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Re: SUGGESTED SOLUTION....
« Reply #2 on: November 06, 2009, 11:28:33 am »
Part 2

physics

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Re: SUGGESTED SOLUTION....
« Reply #3 on: November 06, 2009, 11:29:54 am »
nice! :)
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chelo

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Re: SUGGESTED SOLUTION....
« Reply #4 on: November 06, 2009, 11:30:15 am »
Part 3 i couldn't do the last question

saymun

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Re: SUGGESTED SOLUTION....
« Reply #5 on: November 06, 2009, 11:33:20 am »
i think you made a mistake on 10a, 8^(-2/3)/3 =/= 3/4

8^(-2/3)/3 = 1/3 * 1/8^(2/3) = 1/3 * 1/4 = 1/12
« Last Edit: November 06, 2009, 11:34:59 am by saymun »

Chocolate01

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Re: SUGGESTED SOLUTION....
« Reply #6 on: November 06, 2009, 11:34:47 am »
For Q2a do you have to put the absolute signs in? as it asks for AN antiderivative. so wouldn't it still an anti derivative without the abs signs?

TrueTears

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Re: SUGGESTED SOLUTION....
« Reply #7 on: November 06, 2009, 11:38:47 am »
For Q2a do you have to put the absolute signs in? as it asks for AN antiderivative. so wouldn't it still an anti derivative without the abs signs?


Yes must put mod signs.
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kbmj

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Re: SUGGESTED SOLUTION....
« Reply #8 on: November 06, 2009, 11:42:11 am »
hey do u rkn ill lose a mark for not expressing
6/4 as 3/2 in the log question and also
i said that you could bring the 2 to to the top and square the -1
allowing the log to occur
and that very last one i said it was a right point estimate no?

noble park

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Re: SUGGESTED SOLUTION....
« Reply #9 on: November 06, 2009, 11:45:26 am »
hey i how do u derive 2x^2

jakeburn

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Re: SUGGESTED SOLUTION....
« Reply #10 on: November 06, 2009, 11:47:46 am »
are u sure about the log question? and the ommision of -1? it is the only mark i (may have) dropped!!!!

kdgamz

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Re: SUGGESTED SOLUTION....
« Reply #11 on: November 06, 2009, 12:08:58 pm »
For Q2a do you have to put the absolute signs in? as it asks for AN antiderivative. so wouldn't it still an anti derivative without the abs signs?


Yes must put mod signs.

wud u lose a mark though?

lucyk

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Re: SUGGESTED SOLUTION....
« Reply #12 on: November 06, 2009, 12:17:14 pm »
how many marks would you lose for having +c on the end of the antidiff question?

Pineapple

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Re: SUGGESTED SOLUTION....
« Reply #13 on: November 06, 2009, 12:28:41 pm »
I put +c on the end of the anti-diff q, but i said 'where c is a real constant', would I still lose the mark?
also, if I had x= +/- 2/3 then x= 2/3 because x>0, would I lose a mark because x=-3/2 isn't correct
? (should be -1)

hopefully this doesn't mean exam 2 will be a bitch...

TrueTears

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Re: SUGGESTED SOLUTION....
« Reply #14 on: November 06, 2009, 12:29:25 pm »
For Q2a do you have to put the absolute signs in? as it asks for AN antiderivative. so wouldn't it still an anti derivative without the abs signs?


Yes must put mod signs.

wud u lose a mark though?
Yes 1 mark would definitely be lost.

I put +c on the end of the anti-diff q, but i said 'where c is a real constant', would I still lose the mark?
also, if I had x= +/- 2/3 then x= 2/3 because x>0, would I lose a mark because x=-3/2 isn't correct
? (should be -1)

hopefully this doesn't mean exam 2 will be a bitch...
1 mark off for getting incorrect answer.
PhD @ MIT (Economics).

Interested in asset pricing, econometrics, and social choice theory.