Methods 2009 Exam 1 Suggested Solutions

[simpak]

I'm pretty sure you get both marks when that happens?
To do that question, if I'm not mistaken, the probability acquired in b was required in c.
If you worked out c correctly using the answer you obtained in b, then I thought you get consequential marks and method marks.
Your answer is consequential.

[jasrulz63]

Want it into a PDF again TT?

[TrueTears]

Want it into a PDF again TT?

That would be greatly appreciated! Thanks xD

I'll post link up in OP.

[jasrulz63]

msg195356 date=1257486628]
That would be greatly appreciated! Thanks xD

I'll post link up in OP.

Haha same to you for doing the solutions;
http://www.mediafire.com/file/xmdjyrwniwd/TT's Suggested Solutions for Methods!.pdf

[TrueTears]

msg195356 date=1257486628]
That would be greatly appreciated! Thanks xD

I'll post link up in OP.

Haha same to you for doing the solutions;
http://www.mediafire.com/file/xmdjyrwniwd/TT's Suggested Solutions for Methods!.pdf

Awesome, thanks again.

[jasrulz63]

No worries. Just make sure it's in the url tags, or it doesn't work.

[kamil9876]

I see a 'clearly' in one of the proofs - how amusing.  I'm sure VCAA won't mind though.  Perhaps it is clear?

hah, is the use of this taboo in mathematics?

[TheJosh]

should be

Is this the right answer???

[tomygun_123]

should be

Is this the right answer???

yeah it is

[kayf]

Thanks for this, you're a babe.  (or whoever did this)

Lost seven marks, it looks like - not brilliant but it was always destined to be in my bottom two. I only wasted two or so hours revising, anyway.

[homghomg1]

I think the main point for the last question was for you to recognise that the derivative function is a decreasing one for x > 0, and the linear approximation assumes that the gradient is constant (hence the reason it's called linear approximation, straights lines have a constant gradient), and does not account for the fact that the gradient of f(x) is always decreasing for x > 0.

I'm not too sure about the h value being too big though, it's appropriate to account for inaccuracy of the approximation, but doesn't tell us why the approximation is greater, which is what the question asked. You may or may not get the mark.

Also, for the inverse function question:
"Many students did not give the domain. It is important that students realise that a function consists of two parts – the
domain and the rule."

This is a quote from VCAA 07 paper 2, where the question asked for the inverse function
You often get questions which just ask for the rule, which is why in that case you don't have to put the domain. A rule is different than a function. As VCAA said, a function consists of a rule AND a domain, so forgetting to put the domain will definitely cost a mark

[TrueTears]

I think the main point for the last question was for you to recognise that the derivative function is a decreasing one for x > 0, and the linear approximation assumes that the gradient is constant (hence the reason it's called linear approximation, straights lines have a constant gradient), and does not account for the fact that the gradient of f(x) is always decreasing for x > 0.

I'm not too sure about the h value being too big though, it's appropriate to account for inaccuracy of the approximation, but doesn't tell us why the approximation is greater, which is what the question asked. You may or may not get the mark.

Also, for the inverse function question:
"Many students did not give the domain. It is important that students realise that a function consists of two parts – the
domain and the rule."

This is a quote from VCAA 07 paper 2, where the question asked for the inverse function
You often get questions which just ask for the rule, which is why in that case you don't have to put the domain. A rule is different than a function. As VCAA said, a function consists of a rule AND a domain, so forgetting to put the domain will definitely cost a mark

Very well said.