Methods 2009 Exam 1 Suggested Solutions

[TrueTears]

A question for TT,

for the last question, if your answer was the following, do you think one would gain the mark?

-the approxmiation f(x+5) ... relies on a small value of h
-as h (0.06) is not small enough, i.e. too large, the approxmiation will be inaccurate.
-therefore, the approxmiated value will be greater than the exact value of 8.06^1/3

Yeap that's fine, that's what approximation/integration is all about, making the 'h' infinitely small for integration, thus the larger it gets the more inaccurate. However I think you should have mentioned what NE2000 said because having a large h doesn't always mean overestimate, it could mean underestimate. However given the question was 1 mark, I think that should suffice.

[Yoshi]

Hey for question 2b I messed up my integral, divided x by 1/2 rather than 3/2. Have I lost all three marks for that stupid error?

Sorry for self quoting but does anyone know? Do I at least get something for showing I know how a definite integral works?  

[NE2000]

OK stop raging at TT

http://www.vcaa.vic.edu.au/vce/studies/mathematics/methods/assessreports/2007/mm2_assessrep_07.pdf

Q4bi. : you had to find the domain for the final mark

The question itself was specifically no more or more less than "find the inverse function h-1"

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Had to repeat this post lol seeing as the argument rages on

[mankay]

well the answer with the increasing gradient shit is the offical answer as in the marking scheme (most likely), so i was just wondering whether my alternative answer would be considered  correct (even though it technically doesn't prove/explain what is asked)?

[NE2000]

Hey for question 2b I messed up my integral, divided x by 1/2 rather than 3/2. Have I lost all three marks for that stupid error?

Sorry for self quoting but does anyone know? Do I at least get something for showing I know how a definite integral works?  

No you would not have lost all three marks. You may have lost 2 as one methods mark would probably be integrating correctly

[mankay]

ok cheers TT

[Yoshi]

Alright, thanks NE2000, I think I'll stop stressing myself for now.

[nadine]

38/40 LOVING LIFE AT THE MOMENT

[jrdaniell]

in the log equation with x, are you certain that x must be greater than zero, for there is a 2 out the front and the question stated no domain, thus -1 should be a perfectly acceptable answer as well as 3/2.

[cjays66]

OK stop raging at TT

http://www.vcaa.vic.edu.au/vce/studies/mathematics/methods/assessreports/2007/mm2_assessrep_07.pdf

Q4bi. : you had to find the domain for the final mark

The question itself was specifically no more or more less than "find the inverse function h-1"

----------------

Had to repeat this post lol seeing as the argument rages on

Many students did not give the domain. It is important that students realise that a function consists of two parts – the
domain and the rule.

[10weid]

TT,

if i didnt write the domain in the form R/(-4) ,
rather i wrote the inverse, x ≠ -4 ,
do i get the mark for the domain?

[majo]

i know this post is not in the correct place, but i thought i should just ask here instead of making a new thread.

to get a raw score of 30 in mm, what scores do u need to get?

[dezz]

how many marksyou think ill lose for using .6 instead of .06 on the approximation question?
dont know how i managed that.
argh, my blindness.
but yea paper was pretty easy, finished in 25minutes. argh hope i dont loose to many marks for the approximation.

just raising my unanswered question again
also, would you lose any marks for not putting a modulus for the log antidiff question?
argh stupid mistakes.

[TrueTears]

TT,

if i didnt write the domain in the form R/(-4) ,
rather i wrote the inverse, x ≠ -4 ,
do i get the mark for the domain?

Should be fine IMO, implies that it can be anything except -4 so yeah I'd say you'd get the mark.

[TrueTears]

how many marksyou think ill lose for using .6 instead of .06 on the approximation question?
dont know how i managed that.
argh, my blindness.
but yea paper was pretty easy, finished in 25minutes. argh hope i dont loose to many marks for the approximation.

just raising my unanswered question again
also, would you lose any marks for not putting a modulus for the log antidiff question?
argh stupid mistakes.

Yeah you'd lose 1 mark.