Hi, just some question ? ^^

[believe_in_you]

10 ppl each roll a fair six sided die once. A player wins if he gets a 6. If less than 6 ppl won, what is a probability that at least 4 people won.

(from CSE test 2008 )

Thanks

[/0]

Let X = number of people who win.
X ~ Bi(10, 1/6)



binomcdf(10,1/6,4,5) = 0.0672897
binomcdf(10,1/6,0,5) = 0.9975618

hence,

[lachymm]

Shit man that looks hard, jibberish to me

[believe_in_you]

thanks

[believe_in_you]

lol, i misinterprete the question. lol
i know what to do now, thanks a lot

[StringFever]

binomcdf(10,1/6,4,5) = 0.0672897

Is the step quoted above able to be done on a graphics calc, or are you using CAS syntax?

[believe_in_you]

I think those steps are from Ti- 83 84 coz i am using them

[believe_in_you]

btw, I've got a problem with ques 293 in checkpoint ( It's from VCAA 2000 anyway). I dont get why the domain of r can include 12.41

[StringFever]

I think those steps are from Ti- 83 84 coz i am using them

There's an argument error when I enter that syntax into my calc.

[/0]

I think those steps are from Ti- 83 84 coz i am using them

There's an argument error when I enter that syntax into my calc.

Most calcs should have a binomcdf function. Which calculator are you using? If you still have the manual it may tell you where to find it.

[dejan91]

I think those steps are from Ti- 83 84 coz i am using them

There's an argument error when I enter that syntax into my calc.

Most calcs should have a binomcdf function. Which calculator are you using? If you still have the manual it may tell you where to find it.

No, I think he meant binomcdf(10,1/6,4,5). That's not possible on a Ti-84, you have to just get binomcdf(10,1/6,4) and binomcdf(10,1/6, 5) and add together.

[Gloamglozer]

binomcdf(10,1/6,4,5) = 0.0672897
binomcdf(10,1/6,0,5) = 0.9975618

Is that the working (calculator syntax) we're supposed to show in CAS exam 2's?

[/0]

No, you can just say

[Gloamglozer]

But if we wrote:

binomcdf(10,1/6,4,5) = 0.0672897

Does that count as a method mark for CAS?

[naved_s9994]

But if we wrote:

binomcdf(10,1/6,4,5) = 0.0672897

Does that count as a method mark for CAS?

No you will get ZERO for the question, despite your answer being correct.
VCAA, around April-March this year, sent emails to many maths teachers,
across Victoria, explaining this exact issue.