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February 22, 2026, 06:05:50 am
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Author Topic: Motion  (Read 1972 times)  Share 

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Studyinghard

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Motion
« on: February 16, 2010, 08:09:03 pm »
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A hockey player receives a ball travelling at 3.5 m/s parallel to the sideline and sends it directly across the
pitch to another player at a speed of 2.5 m/s. The ball of mass 200 g is on the hockey stick for 135 ms.

a) What is the change in velocity of the ball?
Is it just 1 m/s ?

b) What is the average acceleration of the ball?

c) What is the average force applied to the ball by the stick?


Thanks
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QuantumJG

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Re: Motion
« Reply #1 on: February 16, 2010, 08:35:32 pm »
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Quote from: Studyinghard on February 16, 2010, 08:09:03 pm
A hockey player receives a ball travelling at 3.5 m/s parallel to the sideline and sends it directly across the
pitch to another player at a speed of 2.5 m/s. The ball of mass 200 g is on the hockey stick for 135 ms.

a) What is the change in velocity of the ball?
Is it just 1 m/s ?

b) What is the average acceleration of the ball?

c) What is the average force applied to the ball by the stick?


Thanks

a) Let velocity towards the shooter be negative EDIT: Major stuff up  :-[  It can't be 1m/s!!!

c)

    

b) a = 44.4m/s2
« Last Edit: February 16, 2010, 10:10:13 pm by QuantumJG »
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Blakhitman

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Re: Motion
« Reply #2 on: February 16, 2010, 09:19:25 pm »
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shouldn't change in velocity be -1 m/s?

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superflya

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Re: Motion
« Reply #3 on: February 16, 2010, 09:26:23 pm »
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it depends on which direction u take as

i got when taking the initial direction as

when taking the reverse.
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Blakhitman

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Re: Motion
« Reply #4 on: February 16, 2010, 09:31:50 pm »
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yeah should either be -1 or 6.

if were not given which direction to use as - or + we need to assign one and show it right?
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QuantumJG

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Re: Motion
« Reply #5 on: February 16, 2010, 10:14:11 pm »
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Please relook at my post, I made a stuffup! :-[
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superflya

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Re: Motion
« Reply #6 on: February 16, 2010, 10:17:32 pm »
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Quote from: Blakhitman on February 16, 2010, 09:31:50 pm
yeah should either be -1 or 6.

if were not given which direction to use as - or + we need to assign one and show it right?

yes if its not given, u take one direction and u MUST show it as .
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moekamo

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Re: Motion
« Reply #7 on: February 17, 2010, 12:19:34 pm »
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No directions of velocities aren't opposite, they are perpendicular so change in v; you use pythag and must draw a vector triangle of final - initial where younuse arrows for final and initial velocities

look at this: http://vcenotes.com/forum/index.php/topic,22188.0.html
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QuantumJG

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Re: Motion
« Reply #8 on: February 17, 2010, 02:09:20 pm »
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Quote from: moekamo on February 17, 2010, 12:19:34 pm
No directions of velocities aren't opposite, they are perpendicular so change in v; you use pythag and must draw a vector triangle of final - initial where younuse arrows for final and initial velocities

look at this: http://vcenotes.com/forum/index.php/topic,22188.0.html

Ahh s**t!

Ok I'm going to use vectors to simplify things!

u = (0,-3.5)m/s & v = (-2.5,0)m/s

a) v = v - u = (-2.5,3.5)m/s
   |v| = 4.30m/s

b) v = at a = 31.86m/s

c) F = ma F = 6.37N 
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Blakhitman

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Re: Motion
« Reply #9 on: February 17, 2010, 03:56:43 pm »
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Ahh yeah is that what it meant, I thought of that, but assumed it was just worded badly or something.
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QuantumJG

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Re: Motion
« Reply #10 on: February 17, 2010, 05:10:07 pm »
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Quote from: Blakhitman on February 17, 2010, 03:56:43 pm
Ahh yeah is that what it meant, I thought of that, but assumed it was just worded badly or something.

Lol, I don't even play hockey.
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Blakhitman

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Re: Motion
« Reply #11 on: February 17, 2010, 05:29:51 pm »
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Quote from: QuantumJG on February 17, 2010, 05:10:07 pm
Quote from: Blakhitman on February 17, 2010, 03:56:43 pm
Ahh yeah is that what it meant, I thought of that, but assumed it was just worded badly or something.

Lol, I don't even play hockey.

Yeah, lol, that was a bad example/question.
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