A question that was answered

[run-bandit]

Does Chapter 4 question 2b in Jacaranda Physics: does it imply that there is another resister in addition to the single one shown in the diagram (a standard voltage divider with r1 = 2.2k ohms and r2=4.4k ohms and battery = 9V? since the question is:

Q) what is the output voltage of circuit if a load of resisoance 4.4k ohms is conected across the output terminals of the voltage divider?

and the  

book answer is

A) effective = 1/4.4 + 1/4.4 = 2.2k ohms so Vout=3.0

I did not make the assumption i have proposed when I first did the question. as a result, my answer was 6V with the R effective being the full 4.4k ohms for R2 (which i think the solutions are talking about)

[run-bandit]

please! urgent! desperate :D:D:D:

[/0]

Which 'output terminals' is the 4.4k ohm resistor connected across?

If it's connected across the 4.4k resistor output terminals (as the working seems to show), then and thus the voltage output is 4.5V?

[QuantumJG]

Could you post up the diagram? If one exists

[run-bandit]

It is across the 4.4 one like you suggested except it is at the bottom if that makes a difference.

[Blakhitman]

I think this is the diagram in question

[run-bandit]

YES!

I think this is the diagram in question

I GIFT YOU 1000 INTERNETS!!

thank you!!

[Blakhitman]

You're welcome mate, sorry I can't help with the actual question though

[run-bandit]

can anyone?
anyone at all

[Mao]

Components connected across V-Out usually has a very high effective resistance compared to R1 and R2. The voltage divider formula is only an approximation of what actually happens.

In this case, however, the component connected across V-Out is a simple resistor, and it has the same resistance as R2. Hence, treat it as a simple resistor circuit.

[run-bandit]

Components connected across V-Out usually has a very high effective resistance compared to R1 and R2. The voltage divider formula is only an approximation of what actually happens.

In this case, however, the component connected across V-Out is a simple resistor, and it has the same resistance as R2. Hence, treat it as a simple resistor circuit.

In most resistor circuits Vout doesn't automatically have the same resistance as R2...

[Mao]

Components connected across V-Out usually has a very high effective resistance compared to R1 and R2. The voltage divider formula is only an approximation of what actually happens.

In this case, however, the component connected across V-Out is a simple resistor, and it has the same resistance as R2. Hence, treat it as a simple resistor circuit.

In most resistor circuits Vout doesn't automatically have the same resistance as R2...

They specified the resistance to be 4.4kohms

"a load of resisoance 4.4k ohms is conected across the output terminals"

[Collin Li]

Great marketing (re: your title)

Definitely scored a click/eyeball from me

You're gonna get places, hahaha.

[run-bandit]

Components connected across V-Out usually has a very high effective resistance compared to R1 and R2. The voltage divider formula is only an approximation of what actually happens.

In this case, however, the component connected across V-Out is a simple resistor, and it has the same resistance as R2. Hence, treat it as a simple resistor circuit.

In most resistor circuits Vout doesn't automatically have the same resistance as R2...

They specified the resistance to be 4.4kohms

"a load of resisoance 4.4k ohms is conected across the output terminals"

But if you take it as just the 4.4k ohms then the solutions are wrong?

[physics]

This is really hardcore physics to me and i rerad the thread halfway beofre i found it too confusing so i went to

http://library.thinkquest.org/10796/ch4/ch4.htm

its a feel good site where the questions are simple and are explained