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March 09, 2026, 08:51:49 pm
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Author Topic: Calculating pH  (Read 605 times)  Share 

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Nomvalt

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Calculating pH
« on: March 16, 2010, 03:51:11 am »
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Calculate the pH of the following solution:

KOH of concentration 1.5 mol/L.

In the worked solutions it shows:

[OH-] = 1.5 M
= 10^0.18 ---------------------> but how do you convert 1.5 to 10^0.18?

We have [H+][OH-] = 10^-14
[H+] = 10^-14/10^0.18
= 10^-14.18

pH = 14.2


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moekamo

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Re: Calculating pH
« Reply #1 on: March 16, 2010, 05:47:33 am »
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m@tty

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Re: Calculating pH
« Reply #2 on: March 16, 2010, 05:35:11 pm »
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Isn't it meant to be log base 10?
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2009/2010: Mathematical Methods(non-CAS) ; Business Management | English ; Literature - Physics ; Chemistry - Specialist Mathematics ; MUEP Maths

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moekamo

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Re: Calculating pH
« Reply #3 on: March 16, 2010, 05:45:25 pm »
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it can be, it doesnt matter, both give the same answer, although log base 10 would make more sense and make it a bit easier...
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m@tty

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Re: Calculating pH
« Reply #4 on: March 16, 2010, 05:57:30 pm »
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Oh wait I see now: you were just finding an exponent...
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2009/2010: Mathematical Methods(non-CAS) ; Business Management | English ; Literature - Physics ; Chemistry - Specialist Mathematics ; MUEP Maths

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