Homework Help :)

[rainbows.]

I was wondering, I dont remember the question really, but i think its

Prove/expand/solve/whatever it is of something cos(x/2).. I know im not really asking a question but i remember it has something about a cos(x/2) i need to remember about it =="

[superflya]

lol wah?

[the.watchman]

lol wah?

LOL I don't think we can do much without the question

[rainbows.]

Umm, i think the question was something double angle formula related to the cos(x/2) like using the double angle formula to prove it ?

[superflya]

yea umm prove = wat?

[rainbows.]

Urgh.. im trying to find the question ==" *runs around room, looking through piles of clothes and books everywhere*

Randomly can someone express this 1 + tan(x)i in modulus-argument form, 0 less than x less than pi/2

i = complex

[m@tty]

I think...

That should be the modulus; but what is 'modulus-argument form'?

EDIT: You could have also just taken the sum of the squares of the imaginary and real parts and square rooted them.

ie.

And the Pythagorean identity states:






So

[rainbows.]

Im not sure, but your right (Y)

[superflya]

mod-arg form is the same as polar form.

[rainbows.]

Oh ah..

[m@tty]

mod-arg form is the same as polar form.

I've never heard of it before... :\

[the.watchman]

mod-arg form is the same as polar form.

I've never heard of it before... :\

LOL the modulus is the co-efficient of the 'cis' or |z|
The argument is the angle taken by the 'cis'

[m@tty]

I know what modulus and argument are, I also know what polar form is. I just didn't know that....

Wait, now it makes sense, Magnitude-Angle form -- of course it's polar! :buck2:

[samuch]

mod-arg form is the same as polar form.

I've never heard of it before... :\

LOL the modulus is the co-efficient of the 'cis' or |z|
The argument is the angle taken by the 'cis'

you make me depressed because you are in year 11 and you know all this!!!
*wishes that i was like you last year*

[the.watchman]

I know what modulus and argument are, I also know what polar form is. I just didn't know that....

Wait, now it makes sense, Magnitude-Angle form -- of course it's polar :buck2:

Haha, now you get it

mod-arg form is the same as polar form.

I've never heard of it before... :\

LOL the modulus is the co-efficient of the 'cis' or |z|
The argument is the angle taken by the 'cis'

you make me depressed because you are in year 11 and you know all this!!!
*wishes that i was like you last year*

Well, we don't do anything in GMA, so I learn myself