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October 31, 2025, 12:16:12 am

Author Topic: FREE KARMA ~ yes another question thread . . ;]  (Read 5208 times)  Share 

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crayolé

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FREE KARMA ~ yes another question thread . . ;]
« on: April 07, 2010, 09:55:14 pm »
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I'm going to stop flooding up the board with topics and just stick to this one ;]

So first up,

I had a question that asked me to find the details of the graph
The answers say there is an assymptote at y=0 however, if you sub in x=0 then you get the point (0,0)
Hence the graph touches the assymptote, how does that work? I thought the graph only approached the assymptote?

brightsky

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Re: FREE KARMA ~ yes another question thread . . ;]
« Reply #1 on: April 07, 2010, 10:04:23 pm »
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To find the y-axis, let :



To find the x-axis, let



Either or

The latter is impossible, hence is the only solution.

So the graph goes through (0,0).

As for the asymptote, the range of the graph is . y can never be a negative number, but it can be 0, i.e. when x = 0.
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Albeno69

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Re: FREE KARMA ~ yes another question thread . . ;]
« Reply #2 on: April 07, 2010, 10:05:25 pm »
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good luck with getting into dentistry i know a dentist and he said its very hard to get into and you have a lot of drop outs.lol good luck.

crayolé

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Re: FREE KARMA ~ yes another question thread . . ;]
« Reply #3 on: April 07, 2010, 11:09:38 pm »
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Thanks ;]

How do i turn this into the general hyperbola form?


superflya

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Re: FREE KARMA ~ yes another question thread . . ;]
« Reply #4 on: April 07, 2010, 11:13:56 pm »
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long divide
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the.watchman

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Re: FREE KARMA ~ yes another question thread . . ;]
« Reply #5 on: April 07, 2010, 11:14:34 pm »
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Long divide, or:

Remember, remember the 5th of November

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m@tty

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Re: FREE KARMA ~ yes another question thread . . ;]
« Reply #6 on: April 07, 2010, 11:22:27 pm »
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Not that it makes much difference, buuut... I would do it this way(the difference is in the second step):



...
« Last Edit: April 07, 2010, 11:27:50 pm by m@tty »
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crayolé

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Re: FREE KARMA ~ yes another question thread . . ;]
« Reply #7 on: April 07, 2010, 11:25:44 pm »
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Hmm, sorry for my stupidity but how would you do it by long division?

I dont think I understand the way you guys are doing it

Thanks for the responses so far though ;]

the.watchman

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Re: FREE KARMA ~ yes another question thread . . ;]
« Reply #8 on: April 07, 2010, 11:29:19 pm »
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        -3____
-x+4 | 3x-2
         3x-12
            10

So you have

Hope that came out ok :)
Remember, remember the 5th of November

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2011 - Eng - Phys - Chem - Spesh - Latin - UMAT
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crayolé

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Re: FREE KARMA ~ yes another question thread . . ;]
« Reply #9 on: April 09, 2010, 12:28:11 pm »
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Thank you ;] I think i understand now

Whats the name of the method that m@tty used?

How would I solve for x?



Heres my working so far but I have trouble going any further :/






« Last Edit: April 09, 2010, 12:30:34 pm by Tezza »

m@tty

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Re: FREE KARMA ~ yes another question thread . . ;]
« Reply #10 on: April 09, 2010, 12:31:43 pm »
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It's called synthetic devision.

Just transpose:







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crayolé

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Re: FREE KARMA ~ yes another question thread . . ;]
« Reply #11 on: April 09, 2010, 12:37:13 pm »
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Oh sorry, How would you find the x intercepts? Would you use the same method?

Thanks a lot by the way <3 My crappy school never teaches this kind of stuff. I finally understand
« Last Edit: April 09, 2010, 12:40:17 pm by Tezza »

brightsky

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Re: FREE KARMA ~ yes another question thread . . ;]
« Reply #12 on: April 09, 2010, 12:42:54 pm »
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Yeah, let y = 0 and solve.
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the.watchman

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Re: FREE KARMA ~ yes another question thread . . ;]
« Reply #13 on: April 09, 2010, 12:43:16 pm »
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To find x-intercepts, the other form is easier:

Let

So ,     
Remember, remember the 5th of November

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m@tty

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Re: FREE KARMA ~ yes another question thread . . ;]
« Reply #14 on: April 09, 2010, 12:44:16 pm »
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Yeah, same thing. Just let y=0.

No problem. :)

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