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September 16, 2025, 04:38:46 am

Author Topic: Using Equations to Solve a Problem - Need Help to solve these without a calculat  (Read 2626 times)  Share 

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chuckjefster90

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Hey Guys, I'm unable to solve this problems. Would you be able to help me solve them? The answers are at the bottom, I just need to know how to get them. Thanks Heaps.

1. After spending 5/8 of his salary, Tom has $315 left. What is his salary?

2. 11,12,13 are consexutive integers. Find another 3 consecutive integers which add to 114.

3. A square and an equilateral triangle have the same perimeter. The sides of the triangle are 4cm longer than the sides of the square.
    How long is one side of the square?

4. If Mrs Nguyen is 38 years old and her daughter is 8 years old, in how many years will Mrs Nguyen be 3 times as old as her daughter?

5. Tim runs between 2 places, A and B at 10km/hr and cucles back again at 20 km/hr. The total time taken to run and cucle is 3 hours. If the disance between A and B is x kim, form an equation in x and solve it to find the distance between A and B.

6. THe sum of the interior angles of a polygon with 'n' sides is (2n-4) right angles. If each interior angle is a regular polygon is 135 degrees, how many sides has the polygon?

7. The hypotenuse of a right angles triangle is (x + 5) cm in length and the other 2 sides are 5 cm and (x + 4) cm. Use the Theorem of Pythagoras to write an equation in x and solve it to find the lengths of the unknown sides of the triangle.

Answers:
1) $840         2) 37,38,39           3) 12 cm        4) 7 Years         5) 20 km          6) 8 (an octagon)         7) 12 and 13 cm

the.watchman

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1)



2) Let x be the middle number







So the numbers are 37, 38 and 39



3)





4)





I'm going out now, someone wanna take over? :P
« Last Edit: April 18, 2010, 05:45:38 pm by the.watchman »
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superflya

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q2) n+n+1+n+2=114       3n+3 =114  n=37 so 37,38,39
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m@tty

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5.









6.

Note that the number of sides is the number of angles.







7. By Pythagoras for a right angled triangle

So,







So lengths are 5cm, 12cm and 13cm.
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7. The hypotenuse of a right angles triangle is (x + 5) cm in length and the other 2 sides are 5 cm and (x + 4) cm. Use the Theorem of Pythagoras to write an equation in x and solve it to find the lengths of the unknown sides of the triangle.

(x+5)2 = 52 + (x+4)2

x2 + 10x + 25 = 25 + x2 + 8x +16

2x = 16
x= 8

Sub x into the sides,
8+5 = 13 and 8+4 = 12
:)

Try to remember that 3, 4, 5 and 5, 12, 13 form right angle triangles.
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3)


Hey watchman, is that some kind of formula? :D
I go about doing it this way:

let side length of square be x
4x = 3(x+4)
And then solve for x.

And oops, sorry, just found out that matty did qn 7 lol
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the.watchman

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Nope, it's exactly the same as what you did, except I couldn't be bothered defining a variable :P
Remember, remember the 5th of November

2010 - MM CAS (47) - Cisco 1+2 (pass :P)
2011 - Eng - Phys - Chem - Spesh - Latin - UMAT
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chuckjefster90

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you guys are legends!
Thanks heaps!!! :)


chuckjefster90

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yeahh further haha
forgot all of it haha
hey can you like explain q3?
im still a bit confused on that

chuckjefster90

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wait no worries i got it now :)

chuckjefster90

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hey watchman, sorry third comment but for question four what is 'n' suppose to stand for?

thanksss

the.watchman

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It stands for the no. of years

... after which the conditions set out by the question are met :P
Remember, remember the 5th of November

2010 - MM CAS (47) - Cisco 1+2 (pass :P)
2011 - Eng - Phys - Chem - Spesh - Latin - UMAT
ATAR - 99.00+ plz... :)

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chuckjefster90

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thankss this all helped me so mcuh :)
ill be asking you guys defs if i need help!

thanks again :D

the.watchman

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thankss this all helped me so mcuh :)
ill be asking you guys defs if i need help!

thanks again :D

No probs, happy to help :)
Remember, remember the 5th of November

2010 - MM CAS (47) - Cisco 1+2 (pass :P)
2011 - Eng - Phys - Chem - Spesh - Latin - UMAT
ATAR - 99.00+ plz... :)

Feel free to PM me for anything :D

crayolé

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What further module is this?