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October 17, 2025, 08:46:29 am

Author Topic: How was it?  (Read 35578 times)  Share 

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fdsfsgdfgdf

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Re: How was it?
« Reply #45 on: June 08, 2010, 02:24:52 pm »
I got ABB for the graphs question

and LOL my calculator was in radians moed so i got 6.3 degrees for the banked curve one even though I had the correct working out

And I am really really confused about the 0J vs 4J question. I got 4J, but physics teacher says 0J =/ Such a confusing question =/

And haha I was going really slow at first...I saw i was at question 8 for motion when 30 minutes already passed >.< So I quickened up and finished with 20 mins to go lol...then i spent the last 20 minutes checking motions questions i had asterixed (there weren't really any contentious question in electricity or strctures)
Is it 0J!!! Damn!!!!!!!!!!! I don't get why the graph is B for last one?

in my text book it says in a inelastic collision the KE is converted but momentum is conserved. lucky i read the book this morning

sasha

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Re: How was it?
« Reply #46 on: June 08, 2010, 02:25:00 pm »
pretty sure the projectile motion was around 63m

Cthulhu

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Re: How was it?
« Reply #47 on: June 08, 2010, 02:25:40 pm »
I dont suppose anyone has a copy of the exam?

kyzoo

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Re: How was it?
« Reply #48 on: June 08, 2010, 02:26:52 pm »
Momentum is conserved regardless of whether the collision is inelastic or not. And I spent my last 15 minutes on that 0J vs4J spring question >.< Omg like the principles don't match the calculations.
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curious111

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Re: How was it?
« Reply #49 on: June 08, 2010, 02:27:06 pm »
The projectiles one confused me for a sec, when i calculated the final vertical velocity to be the EXACT same as the distance lol (63.25). Then i realised it makes sense because the initial velocity was 10m/s horizontal and the accelration was obviously 10.

So yeah, 63.25 m, and 64.something for the final velocity.

sasha

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Re: How was it?
« Reply #50 on: June 08, 2010, 02:27:45 pm »
The projectiles one confused me for a sec, when i calculated the final vertical velocity to be the EXACT same as the distance lol (63.25). Then i realised it makes sense because the initial velocity was 10m/s horizontal and the accelration was obviously 10.

So yeah, 63.25 m, and 64.something for the final velocity.

yea haha confused me for a sec aswell, but the horiztonal velocity was 10m/s :D

kenhung123

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Re: How was it?
« Reply #51 on: June 08, 2010, 02:27:58 pm »
I got ABB for the graphs question

and LOL my calculator was in radians moed so i got 6.3 degrees for the banked curve one even though I had the correct working out

And I am really really confused about the 0J vs 4J question. I got 4J, but physics teacher says 0J =/ Such a confusing question =/

And haha I was going really slow at first...I saw i was at question 8 for motion when 30 minutes already passed >.< So I quickened up and finished with 20 mins to go lol...then i spent the last 20 minutes checking motions questions i had asterixed (there weren't really any contentious question in electricity or strctures)
Is it 0J!!! Damn!!!!!!!!!!! I don't get why the graph is B for last one?

in my text book it says in a inelastic collision the KE is converted but momentum is conserved. lucky i read the book this morning
I thought momentum is conserved despite elastic or not and kinetic energy is not conserved in inelastic collisions

fdsfsgdfgdf

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Re: How was it?
« Reply #52 on: June 08, 2010, 02:28:07 pm »
Momentum is conserved regardless of whether the collision is inelastic or not. And I spent my last 15 minutes on that 0J vs4J spring question >.< Omg like the principles don't match the calculations.
what did you get for K? because my calculations were -8J[GPE]+8J[Spring]

Greggler

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Re: How was it?
« Reply #53 on: June 08, 2010, 02:28:35 pm »
k yeah

i kept ending up with 63.25 or sometrhing on my calc for both questinos and i was like....... this cant be right lol but i coudltn think of any other method to use

Blakhitman

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Re: How was it?
« Reply #54 on: June 08, 2010, 02:32:51 pm »
I got ABB for the graphs question

and LOL my calculator was in radians moed so i got 6.3 degrees for the banked curve one even though I had the correct working out

And I am really really confused about the 0J vs 4J question. I got 4J, but physics teacher says 0J =/ Such a confusing question =/

And haha I was going really slow at first...I saw i was at question 8 for motion when 30 minutes already passed >.< So I quickened up and finished with 20 mins to go lol...then i spent the last 20 minutes checking motions questions i had asterixed (there weren't really any contentious question in electricity or strctures)
Is it 0J!!! Damn!!!!!!!!!!! I don't get why the graph is B for last one?

in my text book it says in a inelastic collision the KE is converted but momentum is conserved. lucky i read the book this morning
I thought momentum is conserved despite elastic or not and kinetic energy is not conserved in inelastic collisions

Exactly why it was B.

m@tty

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Re: How was it?
« Reply #55 on: June 08, 2010, 02:33:37 pm »
Nooo, I thought it was asking about kinetic energy :|
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Blakhitman

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Re: How was it?
« Reply #56 on: June 08, 2010, 02:34:30 pm »
And I put 0J aswell...I hope to God I'm right.

Blakhitman

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Re: How was it?
« Reply #57 on: June 08, 2010, 02:35:05 pm »
Anyone else have their multi-choice answers?

m@tty

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Re: How was it?
« Reply #58 on: June 08, 2010, 02:35:35 pm »
Why would there be discrepancy? It said nothing about loss to anything...

EDIT: Yeah. For structures:
1.D
2.B
3.C
4.D
5.C
6.B
7.D
8.A
9.C
10.D
11.D
12.B
« Last Edit: June 08, 2010, 02:37:13 pm by m@tty »
2009/2010: Mathematical Methods(non-CAS) ; Business Management | English ; Literature - Physics ; Chemistry - Specialist Mathematics ; MUEP Maths

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kyzoo

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Re: How was it?
« Reply #59 on: June 08, 2010, 02:35:57 pm »
Momentum is conserved regardless of whether the collision is inelastic or not. And I spent my last 15 minutes on that 0J vs4J spring question >.< Omg like the principles don't match the calculations.
what did you get for K? because my calculations were -8J[GPE]+8J[Spring]
'

k = 50N/m

If you use F = kx you get k = 50
If you use Us = 0.5kx^2 you get k = 100

I would have got this wrong if the same question hadn't been on CSE 2010 lol
2009
~ Methods (Non-CAS) [48 --> 49.4]

2010
~ Spesh [50 --> 51.6]
~ Physics [50 --> 50]
~ Chem [43 --> 46.5]
~ English [46 --> 46.2]
~ UMEP Maths [5.0]

2010 ATAR: 99.90
Aggregate 206.8

NOTE: PLEASE CONTACT ME ON EMAIL - [email protected] if you are looking for a swift reply.