Without dealing with series, we look at the steady-state solution which the series must approach
1.
At steady state, you have 1-x, and I have x. For one iteration (You give me some, I give some back)
 + \frac{you}{2} = you)
or
 = me)
The prior:
+\frac{1-x}{2} = 1-x)
, which solves to x=me=1/3. [the latter gives the same solution]
You give me $ 1/3. Have I earned my karma?
[It's a matter of interpretation though, if the transaction ends on me returning money, you give me $1/3, if the transaction ends on you giving, you give me $2/3, but the system will settle down to alternating between 1/3 and 2/3 for each person.]
Note:
1. It would be fairly easy to show this, as a pair of transactions here can be represented by a 2x2 matrix, and the process here is a dynamical system. Computing the eigenvalues/eigenvectors would show that the dynamical system converges to some eigenvector. I cbf looking it up in the lecture notes right now, but it's definitely doable.