Login

Welcome, Guest. Please login or register.

March 15, 2026, 08:38:32 am

Author Topic: Distance Travelled  (Read 789 times)  Share 

0 Members and 1 Guest are viewing this topic.

wildareal

  • Victorian
  • Forum Leader
  • ****
  • Posts: 595
  • Respect: +4
Distance Travelled
« on: October 02, 2010, 09:49:07 pm »
0
Say you have the function x=2t^2-6t, would the distance traveled for the first 3 secs be the integral of the function from [0.3]
Wildareal '11

Year 11:
Methods 3/4

Year 12:
English 3/4 Latin 3/4 Specialist 3/4 Chem 3/4 Uni Maths

Martoman

  • Victorian
  • Part of the furniture
  • *****
  • Posts: 1476
  • Respect: +11
Re: Distance Travelled
« Reply #1 on: October 02, 2010, 09:57:54 pm »
0
not at all. That is the displacement equation.
2009: Math methods: 50, Psychology: 44
2010: chem 47, further 48, Spesh 49 fml seriously and other yr 11 subs.
2011: Holidaying, screw school.
No. Not azn.
___________________________________
Swedish meal time all the time

sajib_mostofa

  • Victorian
  • Forum Leader
  • ****
  • Posts: 829
  • Respect: +6
Re: Distance Travelled
« Reply #2 on: October 02, 2010, 09:59:32 pm »
0
You will only get the distance if you find the integral of the velocity equation from [0,3]

Martoman

  • Victorian
  • Part of the furniture
  • *****
  • Posts: 1476
  • Respect: +11
Re: Distance Travelled
« Reply #3 on: October 02, 2010, 10:13:06 pm »
0
make sure to always graph the velocity vector. In this case you need to take the negative of the integral as its below the x axis for the interval [0,3]
2009: Math methods: 50, Psychology: 44
2010: chem 47, further 48, Spesh 49 fml seriously and other yr 11 subs.
2011: Holidaying, screw school.
No. Not azn.
___________________________________
Swedish meal time all the time

sajib_mostofa

  • Victorian
  • Forum Leader
  • ****
  • Posts: 829
  • Respect: +6
Re: Distance Travelled
« Reply #4 on: October 02, 2010, 10:14:42 pm »
0
make sure to always graph the velocity vector. In this case you need to take the negative of the integral as its below the x axis for the interval [0,3]

Good point