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October 19, 2025, 06:34:27 am

Author Topic: i  (Read 2181 times)  Share 

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itolduso

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i
« on: October 25, 2010, 10:19:49 pm »
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i^2 = -1
i = ?
sqrt(-1) = ?

brightsky

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Re: i
« Reply #1 on: October 25, 2010, 10:40:45 pm »
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i = sqrt(-1)
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m@tty

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Re: i
« Reply #2 on: October 25, 2010, 10:48:33 pm »
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itolduso

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Re: i
« Reply #3 on: October 25, 2010, 10:58:11 pm »
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what is ln(-1)/pi?

TrueTears

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Re: i
« Reply #4 on: October 25, 2010, 11:00:53 pm »
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i



it's just definitions :D
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m@tty

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Re: i
« Reply #5 on: October 25, 2010, 11:04:28 pm »
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what is ln(-1)/pi?

Oh and realise that this is all imaginary, hence, don't expect to have a conceptual understanding of i or expect to be able to visualise where it would be on a number line...
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itolduso

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Re: i
« Reply #6 on: October 25, 2010, 11:06:31 pm »
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i



it's just definitions :D

What definition are you referring to?

TrueTears

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Re: i
« Reply #7 on: October 25, 2010, 11:07:01 pm »
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sqrt(-1) = i

in fact the proper definition is i^2 = -1 and sqrt(-1) = i is a consequence
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itolduso

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Re: i
« Reply #8 on: October 25, 2010, 11:11:56 pm »
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I havent seen such a definition. Where can i find it?
sqrt(-1) = i,
.: ln(-1)/pi = e^(ipi/2)?

Martoman

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Re: i
« Reply #9 on: October 25, 2010, 11:41:26 pm »
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what is ln(-1)/pi?

Oh and realise that this is all imaginary, hence, don't expect to have a conceptual understanding of i or expect to be able to visualise where it would be on a number line...

I see it on a number line as hovering above it. It adds a dimention to numbers.
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brightsky

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Re: i
« Reply #10 on: October 25, 2010, 11:43:47 pm »
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I havent seen such a definition. Where can i find it?
sqrt(-1) = i,
.: ln(-1)/pi = e^(ipi/2)?

Well it so happens that . Hence plugging in, you get .

And just as m@tty has done above, do some manipulation of this:



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m@tty

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Re: i
« Reply #11 on: October 25, 2010, 11:48:17 pm »
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what is ln(-1)/pi?

Oh and realise that this is all imaginary, hence, don't expect to have a conceptual understanding of i or expect to be able to visualise where it would be on a number line...

I see it on a number line as hovering above it. It adds a dimention to numbers.

Yeah, so its not on the number line. It is separate, a new concept, part of the unknown...

On an Argand diagram you just treat it like you do the vertical axis on the Cartesian plane
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TrueTears

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Re: i
« Reply #12 on: October 25, 2010, 11:50:13 pm »
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what is ln(-1)/pi?

Oh and realise that this is all imaginary, hence, don't expect to have a conceptual understanding of i or expect to be able to visualise where it would be on a number line...

I see it on a number line as hovering above it. It adds a dimention to numbers.
yeah there actually IS a number line for complex numbers (check the wiki link below), in fact our real number line can not represent i, so i is kinda like the imaginary unit for the complex number system, you can think of it as the complex equivalent of a real number line.

I havent seen such a definition. Where can i find it?
sqrt(-1) = i,
.: ln(-1)/pi = e^(ipi/2)?
i dono, elementary algebra textbooks? or just read here

http://en.wikipedia.org/wiki/Imaginary_unit

i forgot the mathematician who formally defined i, maybe it says somewhere in the wiki article.
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kyzoo

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Re: i
« Reply #13 on: October 25, 2010, 11:53:21 pm »
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what is ln(-1)/pi?

Oh and realise that this is all imaginary, hence, don't expect to have a conceptual understanding of i or expect to be able to visualise where it would be on a number line...

I see it on a number line as hovering above it. It adds a dimention to numbers.

Wait a minute...if "i" adds a 2nd dimension to the numbers, then that means there's a 3rd dimenion, and a 4th, and so on?
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Martoman

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Re: i
« Reply #14 on: October 25, 2010, 11:55:34 pm »
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In a sense it adds a a certain dimentionality to them yes.
2009: Math methods: 50, Psychology: 44
2010: chem 47, further 48, Spesh 49 fml seriously and other yr 11 subs.
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No. Not azn.
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