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March 01, 2026, 05:18:15 pm

Author Topic: gen solutions to complex trigs...  (Read 633 times)  Share 

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bar0029

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gen solutions to complex trigs...
« on: November 03, 2010, 03:01:53 pm »
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hi there,
is anyone able to help find the general solution to this equation:

cos(x) + cos(3x) = 1/2
 :)
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Linkage1992

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Re: gen solutions to complex trigs...
« Reply #1 on: November 03, 2010, 03:19:22 pm »
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Is this with the calculator or without?
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chopz

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Re: gen solutions to complex trigs...
« Reply #2 on: November 03, 2010, 03:23:28 pm »
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u mean the one in the sample 2010 questions, pretty sure without calc
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sajib_mostofa

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Re: gen solutions to complex trigs...
« Reply #3 on: November 03, 2010, 03:27:44 pm »
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Thats a crazy Q

costa94

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Re: gen solutions to complex trigs...
« Reply #4 on: November 03, 2010, 04:35:23 pm »
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Use triple angle formula for the cos3x because you need to have only x in the brackets. From there let cos(x) = u and u get 4u^3 etc etc = 1/2, then solve.

JinXi

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Re: gen solutions to complex trigs...
« Reply #5 on: November 03, 2010, 04:53:09 pm »
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cos (x) + cos(3x) = 0.5
cos (x) + cos(2x)cos(2) - sin(2x)sin(x) = 0.5
cos (x) + (1-2sin^2(x))(cos(x))-2sin^2(x)cos(x)=0.5
cos (x) + cos(x)-2sin^2(x)cos(x)-2sin^2(x)cos(x)=0.5
2cos(x) - 4sin^2(x)cos(x)=0.5
2cos(x) -2((1-cos(2x))cos(x)) =0.5
2cos(x) - 2cos(x) + 2cos^2(x)=0.5
cos^2(x) = 0.25
cos(2x) = +- 0.25
2x = pi/3, 2pi/3 + kpi
x = pi/6, 2pi/6 + kpi/2

k= Natural Numbers.

Doubt we nid this in methods  u.u
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