Last Years Multi Q22:

[wildareal]

Consider the region bounded by the x-axis, y-axis, the line with equation y=3 and the curve with equation y=log(x-1)

The exact value of the area of this region is?

Answer is the integral of e^x +1,0,3

Which is the inverse of log(x-1)

How do you realise it is asking for the inverse?

[wildareal]

Dear Wildareal,

You have to integrate the inverse because you are finding the area between the y-axis, x-axis and the graph. Therefore the poles are 0 to 3. You cannot find this area with log(x-1).

[sajib_mostofa]

Or you could simply use the calc

[Jdog]

you answered it yourself??

[wildareal]

Or you find the area of the rectangle: height 3, base e^3+1=3(e^(3)+1)

-Area bounded by graph and x-axis: integral(log(x-1),2,e^(3)+1)

=3e^(3)+3-(2e^(3)+1)

=e^3+2