Author Topic: What's the range of f[x]=a(sin[x]-a)? (Read 1098 times) Tweet Share

Antonyant · « **on:** May 07, 2008, 10:08:39 pm »

my teacher hasnt gone through the sac so... im lost

Captain · « **Reply #1 on:** May 07, 2008, 10:18:03 pm »

Quote from: Antonyant on May 07, 2008, 10:08:39 pm

F(X)=a(sinx-a) it was on my last sac n i got it wrong.
my teacher hasnt gone through the sac so... im lost

$f(x) = asin{(x-a)}$ Is that the problem?
Or is it $f(x) = a(sin{(x)}-a)$

I'm going to assume it was the first one, as the second one is a really stupid question.

$f(x) = asin{(x-a)}$
This is a sine graph. No verticle translations.
Therefore, only thing effecting range is the amplitude. Since it is based around $0$

Range: $[-a, a]$

Please, be clearer with your questions

Edit: Seems you modified the question while I was typing.
In this case

$f(x) = a(sin{(x)}-a)$
$f(x) = asin{(x)}-a^2$
Therefore, since we have a verticle translation of $a^2$ , If a is a negative number, squaring it makes it positive. Translation will always be below the x-axis.

Range: $[-a^2-a, -a^2+a]$

Glockmeister · « **Reply #2 on:** May 07, 2008, 10:21:59 pm »

You mean $f(x) = a(\sin {(x)} - a)$

If that's the ~~cake~~ (I mean case... must have been thinking with portals lol), then the range would would be $[- a - a^{2}, a - a^{2}]$

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Author Topic: What's the range of f[x]=a(sin[x]-a)? (Read 1098 times) Tweet Share

Antonyant

What's the range of f[x]=a(sin[x]-a)?

Captain

Re: WASS DA RANGE OF F(X)=a(sinx-a)????????? it was on my last sac n i got it wrong.

Glockmeister

Re: WASS DA RANGE OF F(X)=a(sinx-a)????????? it was on my last sac n i got it wr

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