Howd you go on the chem exam?

[curious111]

For Q4, what did the poisoning of the catalyst do to the rate of reaction?

I put C for that (that the rate stayed constant). Not sure though. :S

EDIT: Argh this is wrong. Stupid mistake

[10weid]

can sum1 please make a chem thread?

[andy456]

For Q4, what did the poisoning of the catalyst do to the rate of reaction?

A
it essentially removed the catalyst so the rate would drop but then remain constant

[samiira]

can sum1 please make a chem thread?

yeh i reckon

[Xavier1234]

For Q4, what did the poisoning of the catalyst do to the rate of reaction?

I put C for that (that the rate stayed constant). Not sure though. :S

isnt it like saying K is not affected by catalysts hence C concentration is constant? thats what i put in.

[Studyinghard]

For Q4, what did the poisoning of the catalyst do to the rate of reaction?

I put C for that (that the rate stayed constant). Not sure though. :S

isnt it like saying K is not affected by catalysts hence C concentration is constant? thats what i put in.

Rate question is question 4, Q 5 is the concentration question. However we are not arguing for this whether the K has changed we are going the speed of the concentration change which is why I got 4) A and 5)B

[Whatlol]

I said 4 a and 5 c )=

[Xavier1234]

I said 4 a and 5 c )=

same lol. hooray for chem as 10%

[Studyinghard]

I said 4 a and 5 c )=

same lol. hooray for chem as 10%

oh crap, i see how 5 is C now because I thought B because I felt it was asking the concentration after the catalyst was added was it not?

[andy456]

I put 4 A, 5 C
I think 5 is C because catalysts only effect the rate of reaction... nothing else... so it says the system is already at equlibrium so if you remove the catalyst only the rate will change meaning concentration will remain constant. therefore 5 C

[Whatlol]

I said 4 a and 5 c )=

same lol. hooray for chem as 10%

oh crap, i see how 5 is C now because I thought B because I felt it was asking the concentration after the catalyst was added was it not?

it was at equilibrium, so the equilibrium positions shouldnt be affected by the poisoning of the catalyst

[sajib_mostofa]

I said 4 a and 5 c )=

same lol. hooray for chem as 10%

oh crap, i see how 5 is C now because I thought B because I felt it was asking the concentration after the catalyst was added was it not?

Catalyst doesnt have any effect on concentration. It only affects that rate of reaction.

[jayna]

Whats the answer for 4?

[samiira]

I said 4 a and 5 c )=

same lol. hooray for chem as 10%

oh crap, i see how 5 is C now because I thought B because I felt it was asking the concentration after the catalyst was added was it not?

Catalyst doesnt have any effect on concentration. It only affects that rate of reaction.

thats what i thought aswell

[Studyinghard]

touche, i see it. its C
What did people get for 7 and 8