Maths Methods 3/4 Help Thread 2011

[nacho]

dammn
just did neap 2008..
are all of neaps questions legit ? like can they be asked by vcaa?
my neck hurts. finished with like 14 mins left :/


btw;
someone check question 20 MC for me?
i think there is a mistake in the solutions

[Greatness]

It is. I'm just wondering, how do i do it the way you flip it all i.e. x=f(y)

That would probably get messy and i dont think you have to do that in methods.

dammn
just did neap 2008..
are all of neaps questions legit ? like can they be asked by vcaa?
my neck hurts. finished with like 14 mins left :/

Had a quick look at the questions... looks pretty tedious and long. but yeah most of them can be asked by vcaa unlikely tho

[dc302]

I remember disliking NEAP cause their exams seemed a bit out there.. not typical VCAA style.

[Greatness]

I remember disliking NEAP cause their exams seemed a bit out there.. not typical VCAA style.

Really i dont mind Neap theyre actually pretty good compared to other companies. This exam is just harder than others by the looks of it.

[nacho]

I remember disliking NEAP cause their exams seemed a bit out there.. not typical VCAA style.

yea!! screw neap!!
vcaa heff kilb mav ftw!

[duquesne9995]

btw;
someone check question 20 MC for me?
i think there is a mistake in the solutions

Did you get C as your answer?
This is how I did it (although might be wrong)
let x= number of rats cured
in first trial, Pr(x>=1)=0.85
Pr(x=0)=0.15
use binom rule to solve for probability of cure = 0.061......
although this part is kind of unnecessary since all the options have 0.061
you might just want to check that 0.061 works and is the probability of cure
so in second trial, you want Pr(x<=2) which is option C

Anyone done Neap 2011?

[Bozo]

Would you say Kilbaha is much harder than vcaa, cause i did the 2011 kilbaha and i thought it was much harder than vcaa style. Also, i've come across this question in kilbaha 2011 Exam 1 Q5.

The speed v, in metres per seconds, where v(t) = 72/(3t+2)^2 where t >0

Find the distance travelled in metres by the object in the first 2 seconds.

Now, i know that you can anti diff from velocity to distance, but what i did was subbed 2 into the velocity, got the speed, then did d=v*t.   That doesn't work, why?

[b^3]

Velocity is the rate at which displacement is changing over time. i.e.
So find x, we have to do the opposite of the differentiaton, i.e. antidiff it.

So that basically means the displacement is the signed area under a velocity time graph (also note: that veloicty is the area under an acceleration time graph).

But we want distance, so that is the area (not signed area).
So distance =





(hopefully there are no mistakes in there)
d=v*t won't work since the velocity is not constant.

[Bozo]

Makes sense, didn't realize the velocity wasn't constant. Cheers

[mickeymouse]

I remember disliking NEAP cause their exams seemed a bit out there.. not typical VCAA style.

Really i dont mind Neap theyre actually pretty good compared to other companies. This exam is just harder than others by the looks of it.

i like neap too for exam 2

[tattslotto]

Sorry for the noob question but how do you derive ?

[Greatness]

You use chain rule. So bring the power of 4 down, and multiply 8sin(x)^3 by the derivative of sin(x)
so yuo get dy/dx= 8*cos(x)*sin(x)^3 + 5

[stephanton]

hi

i was just wondering if someone could give me a question and its solution using the inter-quartile range method? i think iv come across one... i just cant remember it...
the diff between the 25th and the 75th percentile

thanks.

[Inside Out]

I dont get question 2g extended response vcaa exam 2 2007: how can u know that the available time is 80 minutes what if she had entered the gorge at 12 midnite or spmewhere at the start wouldnt she be dead.The question doesnt say she entered the gorge at 9.20am. someone help this question is driving me nuts

[mickeymouse]

could someone please help clarify --> so if a question states that the hybrid function is
a) continuous
b) smooth
 
what these indicate, I know "smooth" means same gradient? I think I came across a question that had smooth but not continuous?