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March 15, 2026, 05:14:53 am
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Author Topic: Andiio needs help.  (Read 3062 times)  Share 

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mandy

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Andiio needs help.
« on: November 30, 2010, 11:23:53 pm »
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Hey guys, Andiio asked me this question (part b, in particular) before and I can't remember how to do math LOL. So can you guys please take over from here?
The question is in a word document.
We say thanks :)
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Andiio

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Re: Andiio needs help.
« Reply #1 on: November 30, 2010, 11:28:17 pm »
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Could you guys also help with this question please?

Let f(x) = px+q/x+r where x is an element of R\{-r,r}
a) If f(x) = f(-x) for all x, show that f(x) = p for x is an element of R\{-r,r}
b) If f(-x) = -f(x) for x is not equal to 0, find the rule for f(x) in terms of q.

Not sure what a) wanted you to do; I wrote px+q/x+r = q-px/r-x then i was like hm... ahha!

Thanks! :D
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98.40_for_sure

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Re: Andiio needs help.
« Reply #2 on: November 30, 2010, 11:30:43 pm »
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Poor form mandy...
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TrueTears

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Re: Andiio needs help.
« Reply #3 on: November 30, 2010, 11:34:16 pm »
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a) is just to show it's even

b) is to show it's odd
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mandy

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Re: Andiio needs help.
« Reply #4 on: November 30, 2010, 11:35:12 pm »
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Quote from: 99.95_for_sure on November 30, 2010, 11:30:43 pm
Poor form mandy...

Shut up and help Andiio please <3
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98.40_for_sure

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Re: Andiio needs help.
« Reply #5 on: November 30, 2010, 11:36:33 pm »
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Quote from: mandy on November 30, 2010, 11:35:12 pm
Quote from: 99.95_for_sure on November 30, 2010, 11:30:43 pm
Poor form mandy...

Shut up and help Andiio please <3

YOU help him... remember what i taught you. You can do it :)
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mandy

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Re: Andiio needs help.
« Reply #6 on: November 30, 2010, 11:38:59 pm »
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Quote from: 99.95_for_sure on November 30, 2010, 11:36:33 pm
Quote from: mandy on November 30, 2010, 11:35:12 pm
Quote from: 99.95_for_sure on November 30, 2010, 11:30:43 pm
Poor form mandy...

Shut up and help Andiio please <3

YOU help him... remember what i taught you. You can do it :)

You haven't taught me anything, now help him!
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Andiio

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Re: Andiio needs help.
« Reply #7 on: November 30, 2010, 11:40:10 pm »
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Quote from: TrueTears on November 30, 2010, 11:34:16 pm
a) is just to show it's even

b) is to show it's odd

Yea I was thinking along the lines of an even/odd function, but why does it specify '= p' and function 'in terms of q'
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98.40_for_sure

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Re: Andiio needs help.
« Reply #8 on: November 30, 2010, 11:44:19 pm »
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For the question in your word document part b

CY = CX = 3-r
AX = AZ = x-r
AC = AX + XC = x - r + 3 - r = x + 3 - 2r

By pythagoras' theorem:

x^2 + 9 = AC^2

Rest is trivial
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TrueTears

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Re: Andiio needs help.
« Reply #9 on: November 30, 2010, 11:51:26 pm »
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suggestion: long divide through the rational function, the answer is in your face :D (assuming you know how to graph hyperbolas)
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98.40_for_sure

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Re: Andiio needs help.
« Reply #10 on: December 01, 2010, 12:02:48 am »
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Uhh... this is the answer i got?

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taiga

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Re: Andiio needs help.
« Reply #11 on: December 01, 2010, 12:07:05 am »
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bahaha sorry for ignoring message before! I assume you have answer, iff not just give us a yell ill be on longer :)
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Andiio

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Re: Andiio needs help.
« Reply #12 on: December 01, 2010, 12:14:21 am »
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Quote from: 99.95_for_sure on December 01, 2010, 12:02:48 am
Uhh... this is the answer i got?



OH you were supposed to add AX + XC like vectors? I got up to AX and CY and didn't know why the answer was combining the two.. lol thanks!!! :D
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Andiio

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Re: Andiio needs help.
« Reply #13 on: December 01, 2010, 12:15:04 am »
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Will work on the even/odd function q in a bit! :)
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98.40_for_sure

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Re: Andiio needs help.
« Reply #14 on: December 01, 2010, 12:17:37 am »
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Not vectors, they are just lengths. By definition, vectors have direction and magnitude. Haven't you seen despicable me? :P
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